使用附加字段休眠多对多：无法找到具有 id 的实体

Question

我遇到了一个关于 hibernate jpa n...m 请求的问题。我的设置如下所示：

ChatRoom <--> Participant

需要注意的是映射表 RoomParticipant 有一个额外的活动字段：

Room -> RoomParticipant <- Participant
id      id                 id
name    roomId             name
...     participantId      ...
        active

在完成了一些教程并阅读了很多错误修复建议之后，我坚持使用这个设置（使用 Lombok）：

@Entity
@Getter
@Setter
@NoArgsConstructor
@AllArgsConstructor
@ToString
@EqualsAndHashCode
@Table(name = "rooms")
public class Room {

  @Id
  @GeneratedValue(generator = "uuid")
  @GenericGenerator(name = "uuid", strategy = "uuid")
  private String id;

  @OneToMany(mappedBy = "room")
  private List<RoomParticipant> roomParticipants = new ArrayList<RoomParticipant>();

  public void addParticipant(Participant participant) {
    RoomParticipant roomParticipant = new RoomParticipant(this, participant);
    roomParticipants.add(roomParticipant);
    participant.getRooms().add(roomParticipant);
  }
}

// class annotations omitted
public class Participant {  
  @Id
  private String id;

  @Column
  private String name;

  @OneToMany(mappedBy = "participant", cascade = CascadeType.ALL, orphanRemoval = false)
  @JsonIgnore
  private List<RoomParticipant> rooms = new ArrayList<RoomParticipant>();
}

// class annotations omitted
public class RoomParticipant {
  @EmbeddedId
  @JsonIgnore
  private RoomParticipantPK id;

  @ManyToOne (fetch = FetchType.LAZY)
  @MapsId("roomId")
  @JsonIgnore
  private Room room;

  @ManyToOne (fetch = FetchType.LAZY)
  @MapsId("participantId")
  private Participant participant;

  @Column
  private boolean active;

  public RoomParticipant(Room room, Participant participant) {
    this.room = room;
    this.participant = participant;
    this.id = new RoomParticipantPK(room.getId(), participant.getId());
    this.active = true;
  }
}


@Getter
@Setter
@NoArgsConstructor
@AllArgsConstructor
@EqualsAndHashCode
@Embeddable
public class RoomParticipantPK implements Serializable {
  @Column(name="room_id")
  private String roomId;

  @Column(name="participant_id")
  private String participantId;
}

除了 RoomParticipant 之外，类注解都是一样的。 现在，有了这个我有两个函数调用：一个打开一个新房间，这个工作！

  public Room createRoom(String title, String userId, String username) {
     Participant participant = participantRepository.findById(userId).orElse(createParticipant(userId, username));
     Room room = new Room();
     room.setTitle(title);
     room.addParticipant(participant);
     room.setArchived(false); 
     return chatRoomRepository.save(room);
   }

调用此函数后，新房间已创建，新参与者已创建，room_participant 表已正确填写。

但现在我正在尝试加入具有以下功能的房间：

  public Room joinRoom(String roomId, String sessionId, String username) {
    Participant participant = participantRepository.findById(sessionId).orElse(createParticipant(sessionId, username));
    Room room = chatRoomRepository.findById(roomId).orElseThrow(() -> new InvalidRoomException(roomId));
    room.addParticipant(participant);
    return chatRoomRepository.save(room);
  }

由于以下错误，这不起作用：

javax.persistence.EntityNotFoundException: Unable to find ...chatservice.model.entities.RoomParticipant with id ...chatservice.model.entities.RoomParticipantPK@cc9e297f

这两个函数都调用 createParticipant 这是这样的：

  private Participant createParticipant(String userId, String username) {
     return participantRepository.save(new Participant(userId, username, new  ArrayList<RoomParticipant>()));
   }

存储库是 JpaRepository 的单行扩展

public interface ChatRoomRepository extends JpaRepository<Room, String> {}
public interface ParticipantRepository extends JpaRepository<Participant, String> {}

Answer 1

您没有保存在 Room.addParticipant 中创建的 RoomParticipant。

为避免实现额外的RoomParticipantRepsitory，只需将Room.roomParticipants 中的注释更改为

 @OneToMany(mappedBy = "room")

到

 @OneToMany(mappedBy = "room", cascade = CascadeType.ALL, orphanRemoval = true)