如何在数据库中保存带有if条件的html代码[重复]

Question

我在数据库中有一个评分字段。如果 $rating>0 的值，则应禁用该按钮，否则应启用该按钮。我将 HTML 代码保存到数据库以显示。

我试过的是：

 $user_notification->notification ="Delivery date <b>" .$date."</b> and delivery time <b> ".$time." </b> for the truck " .$truck_name. " of mileage ".$mileage_name. " of quantity ".$qty. " has confirmed 
        <br> <a href='#' class='btn btn-primary' >Pay ?</a>
        if(.$rating.'=='.0.'){<a href='/showTransaction/".$buy_id."' class='btn btn-primary' >Review ?</a>}else{<a href='' class='btn btn-primary' disabled >Review ?</a>}";
         $user_notification->save();

数据正在保存，但我在输出中得到的是：

如何避免 if 和 else 在 html 中显示？

Answer 1

您的代码的问题在于，在添加条件以附加到字符串的其余部分之前，您没有关闭字符串。此外，变量不需要在字符串中使用双引号进行转义。

$user_notification->notification = "Delivery date <b>$date</b> and delivery time <b>$time</b> for the truck $truck_name of mileage $mileage_name of quantity $qty has confirmed<br><a href='#' class='btn btn-primary'>Pay ?</a>";

if ($rating == 0) {
    $user_notification->notification .= "<a href='/showTransaction/$buy_id' class='btn btn-primary'>Review ?</a>";
} else {
    $user_notification->notification .= "<a href='' class='btn btn-primary' disabled>Review ?</a>";
}

$user_notification->save();