【发布时间】:2017-03-29 12:05:52
【问题描述】:
我有一个数据框列表,我在下面展示了其中的一些:
> str(ls.df.val.keep)
List of 87
$ AT_VALUES_IMV_EU28_EXTRA :'data.frame': 1554 obs. of 4 variables:
..$ PARTNER : Factor w/ 3 levels "EU28_EXTRA","EU28_INTRA",..: 1 1 1 1 1 1 1 1 1 1 ...
..$ PRODUCT : int [1:1554] 2207 2207 2207 2207 2207 2207 2207 2207 2207 2207 ...
..$ PERIOD : Date[1:1554], format: "2010-01-01" "2010-02-01" "2010-03-01" "2010-04-01" ...
..$ INDICATOR_VALUE: num [1:1554] 1033828 291810 227820 104650 254214 ...
$ AT_VALUES_IMV_EU28_INTRA :'data.frame': 4380 obs. of 4 variables:
..$ PARTNER : Factor w/ 3 levels "EU28_EXTRA","EU28_INTRA",..: 2 2 2 2 2 2 2 2 2 2 ...
..$ PRODUCT : int [1:4380] 2207 2207 2207 2207 2207 2207 2207 2207 2207 2207 ...
..$ PERIOD : Date[1:4380], format: "2010-01-01" "2010-02-01" "2010-03-01" "2010-04-01" ...
..$ INDICATOR_VALUE: num [1:4380] 1894626 2177029 1271173 994368 1746904 ...
$ AT_VALUES_IMV_IN :'data.frame': 6 obs. of 4 variables:
..$ PARTNER : Factor w/ 3 levels "EU28_EXTRA","EU28_INTRA",..: 3 3 3 3 3 3
..$ PRODUCT : int [1:6] 2208 2208 220890 220890 22089069 22089069
..$ PERIOD : Date[1:6], format: "2010-09-01" "2012-07-01" "2010-09-01" "2012-07-01" ...
..$ INDICATOR_VALUE: num [1:6] 58 37 58 37 58 37
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我想对这个列表的元素使用自定义函数 dcast(),这些元素是我的 87 个数据帧。每个数据框的预期结果应如下所示,具体取决于其拥有的列数:
22082027 22082029 22082040 22082062 22082086 22082089 22083011 22083019 22083030 22083041 22083061 22083069 22083071 22083082 22084011
1 NA NA NA NA NA NA 400675 NA 3103 NA 186 NA NA NA 22297
2 NA 2594 NA NA NA NA 667309 3011 NA NA NA NA NA 1916 NA
3 NA NA NA NA NA NA NA NA NA NA NA NA NA 263 93482
4 NA NA NA NA NA NA 503155 4516 NA NA NA NA NA 5359 NA
5 NA 175 NA NA NA NA 226936 4514 NA NA NA NA 39389 NA NA
我已经尝试了各种解决方案和代码片段,但都不起作用:
## First solution
all.cast <- list()
for (i in 1:length(ls.df.val.keep)) {
all.cast[[i]] <- dcast(ls.df.val.keep[[i]], PERIOD ~ PRODUCT, value.var = "INDICATOR_VALUE")
}
ls.df.val.dcas <- list()
ls.df.val.dcas <- lapply(names(ls.df.val.keep), myfunc)
它会产生错误:
Error: value.var (INDICATOR_VALUE) not found in input
Called from: cast(data, formula, fun.aggregate, ..., subset = subset, fill = fill,
drop = drop, value.var = value.var)
第二种解决方案
ls.df.val.dcas < - lapply(ls.df.val.keep, function(x) dcast(x, PERIOD ~ PRODUCT, value.var="INDICATOR_VALUE"))
错误是:
Error in dim(ordered) <- ns :
dims [product 1] do not match the length of object [0]
第三种解决方案
llply(ls.df.val.keep, .fun=function(x) dcast(x, PERIOD ~ PRODUCT, value.var="INDICATOR_VALUE"))
错误是:
Error in do.ply(i) :
task 9 failed - "dims [product 1] do not match the length of object [0]"
In addition: Warning message:
In setup_parallel() : No parallel backend registered
第四个解决方案(绝望一)
all.cast <- list()
for (i in 1:length(ls.df.val.keep)) {
all.cast[[i]] <- dcast(ls.df.val.keep[[i]], PERIOD ~ PRODUCT, value.var = "INDICATOR_VALUE")
}
又报错了:
Error in dim(ordered) <- ns :
dims [product 1] do not match the length of object [0]
很奇怪,如果我输入每个数据框的名称或只是列表的元素,例如ls.df.val.keep[[3]],它们有效!我还有很多其他的事情要使用 lapply 对这个列表做,但我被困在了第一步! 有什么我没看到的吗?
已编辑。
我正在按照@Jake 的要求添加我的数据框数据示例:
> head(ls.df.val.keep[[1]])
PARTNER PRODUCT PERIOD INDICATOR_VALUE
58136 EU28_EXTRA 2207 2010-01-01 1033828
58138 EU28_EXTRA 2207 2010-02-01 291810
58140 EU28_EXTRA 220710 2010-03-01 227820
58142 EU28_EXTRA 220710 2010-04-01 104650
58144 EU28_EXTRA 22071000 2010-09-01 254214
58146 EU28_EXTRA 22071000 2010-10-01 572446
.. .. ..
【问题讨论】:
-
在第二个解决方案中,
val.dcas < -应该是val.dcas <-。 -
你从
all(sapply(ls.df.val.keep, function(x) length(dim(x)) == 2 && all(dim(x) > 0)))得到什么? -
@imo。谢谢。这是一个错字。我编辑了这个问题。错字并没有导致任何错误。
-
@皮埃尔。我得到:[1] 错误
-
它应该返回
TRUE。您的列表中有一个不是有效数组的对象。把上面测试的第一部分改成which(sapply(ls.df.val.keep,.....),就知道问题出在哪里了。
标签: r plyr lapply reshape2 dcast