$unwind 2 字段分别在 mongodb 查询答案

【问题标题】：$unwind 2 fields separately in mongodb query$unwind 2 字段分别在 mongodb 查询
【发布时间】：2017-06-28 11:04:40
【问题描述】：

我想$unwind 2 个字段，school 和 home。数据库结构是这样的；

{ 
    "id" : 1,
    "school" : [
        {
            "path" : "school1", 
            "code" : "code1", 
        }, 
        {
            "path" : "school2", 
            "code" : "code2", 
        }, 
        {
            "path" : "school3", 
            "code" : "code3",
        }, 
        {
            "path" : "school4", 
            "code" : "code4",
        } 
    ], 
    "home" : [
         {
            "path" : "home1", 
            "code" : "homeCode1",
        }, 
        {
            "path" : "home2", 
            "code" : "homeCode2",
        }, 
    ]
}

我想 $unwind school 和 home 字段并将它们中的每一个都设为；

{ 
    "id" : 1,
    "school" : [
        {
            "path" : "school1", 
            "code" : "code1", 
        }
},
{ 
    "id" : 1,
    "school" : [
       {
            "path" : "school2", 
            "code" : "code2", 
        }
},
{ 
    "id" : 1,
    "school" : [
       {
            "path" : "school3", 
            "code" : "code3", 
        }
},
{ 
    "id" : 1,
    "school" : [
       {
            "path" : "school4", 
            "code" : "code4", 
        }
},
{ 
    "id" : 1,
    "home" : [
       {
            "path" : "home1", 
            "code" : "homeCode1", 
        }
},
{ 
    "id" : 1,
    "home" : [
       {
            "path" : "home2", 
            "code" : "homeCode2", 
        }
}

我写的旨在获取上述格式的查询是；

db.collection.aggregate([
    {$unwind: "$school"},
    {$unwind: "$home"}
]).pretty()

但query 是成对出现的；

{
    "id" : 1,
    "school" : {
        "path" : "school1",
        "code" : "code1"
    },
    "home" : {
        "path" : "home1",
        "code" : "homeCode1"
    }
}
{
    "id" : 1,
    "school" : {
        "path" : "school1",
        "code" : "code1"
    },
    "home" : {
        "path" : "home2",
        "code" : "homeCode2"
    }
}
{
    "id" : 1,
    "school" : {
        "path" : "school2",
        "code" : "code2"
    },
    "home" : {
        "path" : "home1",
        "code" : "homeCode1"
    }
}
{
    "id" : 1,
    "school" : {
        "path" : "school2",
        "code" : "code2"
    },
    "home" : {
        "path" : "home2",
        "code" : "homeCode2"
    }
}
{
    "id" : 1,
    "school" : {
        "path" : "school3",
        "code" : "code3"
    },
    "home" : {
        "path" : "home1",
        "code" : "homeCode1"
    }
}
{
    "id" : 1,
    "school" : {
        "path" : "school3",
        "code" : "code3"
    },
    "home" : {
        "path" : "home2",
        "code" : "homeCode2"
    }
}
{
    "id" : 1,
    "school" : {
        "path" : "school4",
        "code" : "code4"
    },
    "home" : {
        "path" : "home1",
        "code" : "homeCode1"
    }
}
{
    "id" : 1,
    "school" : {
        "path" : "school4",
        "code" : "code4"
    },
    "home" : {
        "path" : "home2",
        "code" : "homeCode2"
    }
}

我怎样才能分别$unwind 2 个字段，而不是这种结果对格式？

【问题讨论】：

为什么要投反对票？这不是一个很好解释和直接的问题吗？还是已经回答了，重复？

标签： mongodb mongodb-query aggregation-framework

【解决方案1】：

这是不可能的。对于 MongoDB 3.4，有一个可能的解决方法。 $facet 可用于在同一文档的单个阶段中执行一组以上的管道操作。它对您的情况很有用。

db.collection.aggregate({
    '$facet': {
        'school': [{
            '$unwind': '$school'
        }, {
            '$project': {
                _id: '1',
                school: 1
            }
        }],
        'home': [{
            '$unwind': '$home'
        }, {
            '$project': {
                _id: '1',
                home: 1
            }
        }]
    }
}, {
    '$project': {
        'schoolAndHome': {
            '$setUnion': ['$school', '$home']
        }
    }
}, {
    '$unwind': '$schoolAndHome'
}, {
    '$replaceRoot': {
        'newRoot': '$schoolAndHome'
    }
})

【讨论】：