【发布时间】:2015-04-15 07:29:37
【问题描述】:
我正在尝试在下面的文档中返回数组的某些元素。
{
"_id": 2,
"awardAmount": 6000,
"url": "www.url.com",
"numAwards": 3,
"award": "Faculty Seed Research Grant",
"Type": "faculty",
"Applicates": [
{
"School": "psu",
"Name": "tom",
"URL": "www.url.com",
"Time": "",
"Research": "",
"Budge": 7500,
"appId": 100,
"citizenship": "us",
"Major": "mat",
"preAwards": "None",
"Advisor": ""
},
{
"School": "ffff",
"Name": "KEVIN",
"URL": "www.url.com",
"Time": "5/5/5-6/6/6",
"Research": "topology",
"Budge": 9850,
"appId": 101,
"citizenship": "us",
"Major": "gym",
"preAwards": "None",
"Advisor": "Dr. cool",
"Evaluators": [
{
"abstractScore": 3,
"goalsObjectivesScore": 4,
"evalNum": 1
},
{
"abstractScore": 545646,
"goalsObjectivesScore": 46546,
"evalNum": 2
}
]
}
]
}
如果他们有一个“评估者”字段,我只想要“应用程序”数据。这是我正在尝试的方法
db.coll.find({'Applicates.Evaluators':{'$exists': True }})
这给了我整个文档,但我只想要像这样包含“评估者”字段的“应用”数据。
{
"_id": 2,
"awardAmount": 6000,
"url": "www.url.com",
"numAwards": 3,
"award": "Faculty Seed Research Grant",
"Type": "faculty",
"Applicates": [
{
"School": "ffff",
"Name": "KEVIN",
"URL": "www.url.com",
"Time": "5/5/5-6/6/6",
"Research": "topology",
"Budge": 9850,
"appId": 101,
"citizenship": "us",
"Major": "gym",
"preAwards": "None",
"Advisor": "Dr. cool",
"Evaluators": [
{
"abstractScore": 3,
"goalsObjectivesScore": 4,
"evalNum": 1
},
{
"abstractScore": 545646,
"goalsObjectivesScore": 46546,
"evalNum": 2
}
]
}
]
}
【问题讨论】:
标签: python mongodb pymongo aggregation-framework