如何将 XML 字符串解析为 Java 对象？

Question

我有一个来自 Web 服务的响应作为响应的 XML 字符串。我想解析它并将其转换为 Java 对象。请帮我解决它。我尝试过使用各种库但失败了。都给出了一些例外。

XML 字符串：

<LOGINRESPONSE xmlns:xsd="http://www.w3.org/2001/XMLSchema"     
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" Message="Login Successful"   
    Token="SFTT67FGHUU" DataFormat="CSV" Header="true" Suffix="true"  
    xmlns="http://ws.eoddata.com/Data" />

我使用的代码是：

HttpClient httpclient = new DefaultHttpClient();
HttpGet httpget = new HttpGet(
    "http://<webservice URL>/Login?Username=<username>&Password=<password>");
ResponseHandler<String> responseHandler = new BasicResponseHandler();
String response = httpclient.execute(httpget, responseHandler);
System.out.println(response);
try (ByteArrayInputStream bais = new ByteArrayInputStream(response.getBytes())) {
    Document doc = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(bais);
    System.out.println(doc);
} catch (Exception exp) {
    exp.printStackTrace();
}

但是 doc 以 null 的身份出现。我想从 xml 字符串中提取令牌

Answer 1

您应该能够将String 包装在ByteArrayInputStream 中并将其传递给DocumentBuilder，例如...

String text = "<LOGINRESPONSE xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" Message=\"Login Successful\" Token=\"SFTT67FGHUU\" DataFormat=\"CSV\" Header=\"true\" Suffix=\"true\" xmlns=\"http://ws.eoddata.com/Data\" />";
try (ByteArrayInputStream bais = new ByteArrayInputStream(text.getBytes())) {
    Document doc = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(bais);
} catch (ParserConfigurationException | SAXException | IOException exp) {
    exp.printStackTrace();
}

更新...

要提取属性，您可以使用类似...

NamedNodeMap atts = doc.getDocumentElement().getAttributes();
Node node = atts.getNamedItem("Message");
System.out.println("Message = " + node.getTextContent());

哪个打印...

Message = Login Successful