将 xml 反序列化为列表<t>

Question

我一直在搜索，试图找出我在尝试将某些 xml 反序列化为列表时做错了什么。我能够得到任何东西的脱轨，但答案是，所以脱轨正在工作，但似乎我在课堂装饰上遗漏了一些东西。答案显示在“testObj”中，但为空。

感谢任何帮助。

示例 Xml

<?xml version="1.0" encoding="utf-8" ?>
<TestObj xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<question>
    <stem>this is the question stem</stem>
    <answers>
      <answer>answer 1</answer>
      <answer>answer 2</answer>
      <answer>answer 3</answer>
      <answer>answer 4</answer>
 </question>
 <question .... </question>
 <question .... </question>
 <question .... </question>
</TestObj>

[Serializable]
    public class TestObj
    {
        [XmlElement(ElementName = "question")]
        [XmlElement(typeof(QuestionObj))]
        public List<QuestionObj> Questions { get; set; }

        public int Id { get; set; }
        public string Name;
    }

[Serializable]
    public class QuestionObj
    {
        [XmlElement(ElementName = "stem")]
        public string Stem { get; set; }


        [XmlArray("answers")]
        [XmlArrayItem(ElementName = "answer")]
        [XmlArrayItem(typeof(AnswerObj))]
        public List<AnswerObj> Answers { get; set; }

        public int TestId { get; set; }
        public int Id { get; set; }
    }

[Serializable]
   public class AnswerObj
    {
        [XmlElement(ElementName = "answer")]
        public string Answer { get; set; }

       public int Id { get; set; }
       public int StemId { get; set; }
    }

Object returned:
Question:this is the question stem
   answers
      answer:null
      answer null;
etc

Answer 1

这是 Marc Gravell here 的一个很好的例子：

using System;
using System.Collections.Generic;
using System.Xml.Serialization;

[XmlRoot("user_list")]
public class UserList
{
    public UserList() {Items = new List<User>();}

    [XmlArray("Items")]
    [XmlArrayItem("User", typeof(User))]
    public List<User> Items {get;set;}
}
public class User
{
    [XmlElement("id")]
    public Int32 Id { get; set; }

    [XmlElement("name")]
    public String Name { get; set; }
}

static class Program
{
    static void Main()
    {
        XmlSerializer ser= new XmlSerializer(typeof(UserList));
        UserList list = new UserList();
        list.Items.Add(new User { Id = 1, Name = "abc"});
        list.Items.Add(new User { Id = 2, Name = "def"});
        list.Items.Add(new User { Id = 3, Name = "ghi"});
        ser.Serialize(Console.Out, list);
    }
}

Answer 2

您的序列化属性使序列化程序寻找这样的 xml 结构：

<question>
  <answers>
    <answer>
      <answer>answer text</answer>
      <Id>1234</Id>
      <StemId>1234</StemId>
    </answer>
  </answers>
</question>

您可以将序列化程序更改为使用List<string> 作为答案，或者在 xml 中为每个答案构建一个 AnswerObj（如上所述）。

Answer 3

要获得你期望的 xml 文件，试试这个：

[Serializable]
    public class TestObj
    {
        [XmlElement(ElementName = "question")]
        [XmlElement(typeof(QuestionObj))]
        public List<QuestionObj> Questions { get; set; }

        public int Id { get; set; }
        public string Name;
    }

[Serializable]
    public class QuestionObj
    {
        [XmlElement(ElementName = "stem")]
        public string Stem { get; set; }


        [XmlElement("answers")]
        public List<AnswerObj> Answers { get; set; }

        public int TestId { get; set; }
        public int Id { get; set; }
    }

[Serializable]
   public class AnswerObj
    {
        [XmlElement(ElementName = "answer")]
        public string Answer { get; set; }

       public int Id { get; set; }
       public int StemId { get; set; }
    }

Answer 4

对不起，我需要问一下。您是否正确初始化了 AnswerObj，并在其中设置了答案？ 在 XmlArrayItem 中，您将在其中获得另一个对象，而不仅仅是字符串答案。