【问题标题】:PHP + XPath Query get Child Nodes and their valuesPHP + XPath 查询获取子节点及其值
【发布时间】:2023-03-13 07:51:01
【问题描述】:

我有一个 XML 文件 record.xml,它看起来像:

<record>
    <name>john</name>
    <gender>male</gender>
    <subject>mathematics, english, science</subject>
</record>
<record>
    <name>jamie</name>
    <gender>female</gender>
    <subject>mathematics, science</subject>
</record>
<record>
    <name>jack</name>
    <gender>male</gender>
    <subject>social-science, english</subject>
</record>

我想编写一个 xpath 查询,它将返回 &lt;record&gt; 的所有子节点名称以及关联数组中所有这些子节点的值。

例如:

对于上述 XML 文件的输出数组应该是-

array{
     [0] => array{
                 [name] = 'john',
                 [gender] = 'male',
                 [subject] = 'mathematics, english, science' 
            }
     [1] => array{
                 [name] = 'jamie',
                 [gender] = 'female',
                 [subject] = 'mathematics, science' 
            }
     [2] => array{
                 [name] = 'jack',
                 [gender] = 'male',
                 [subject] = 'social-science, english' 
            }
}

下面是我编写的代码的一部分,它返回所有 &lt;record&gt; 子节点值,但不返回它们的节点名称。

    .......
    .......
    $xmldoc = new DOMDocument();
    $xmldoc->load('record.xml');
    $xpathvar = new Domxpath($xmldoc);
    $res = $xpathvar->query('//record');
    foreach($res as $data){
            //$data do not contain node values
           $arr[] = $data->textContent;
    }
    //process $arr to get required format
     .....
     .....

我只想要一个 Xpath 查询,它将返回子节点名称及其值。

【问题讨论】:

    标签: php xml xpath xpathquery


    【解决方案1】:

    问题是记录,因为节点只是节点层次结构的一部分。您得到的是所有记录,但是您还想下降并从记录的子节点获取数据。一个非常具体的例子是:

    <?php     
    $xmldoc = new DOMDocument();
    $xmldoc->load('record.xml');
    $xpathvar = new Domxpath($xmldoc);
    $res = $xpathvar->query('//record');
    foreach($res as $data){
        $narr = [];
        foreach ($data->childNodes as $cnode) {
            $narr[$cnode->nodeName] = $cnode->nodeValue;
        }
        $arr[] = $narr;
    
    }    
    print_r($arr);
    

    应该输出类似:

    Array
    (
        [0] => Array
            (
                [name] => john
                [gender] => male
                [subject] => mathematics, english, science
            )
    
        [1] => Array
            (
                [name] => jamie
                [gender] => female
                [subject] => mathematics, science
            )
    
        [2] => Array
            (
                [name] => jack
                [gender] => male
                [subject] => social-science, english
            )
    
    )
    

    注意:此解决方案非常具体,如果您有其他嵌套层次结构(我建议您这样做以存储多个主题),则可能会中断。

    【讨论】:

    • 好吧,我认为这足以让我继续前进。谢谢
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