【发布时间】:2013-05-06 20:50:51
【问题描述】:
我正在使用以下模型:Game、User 和 Player,其中 Player 扩展了 User。在这种情况下,Game 和 Player 具有 N:N 的关系,并且 User 扩展了 Confide。所以代码如下:
app/models/Game.php
<?php
class Game extends Eloquent {
protected $guarded = array();
protected $table = 'users';
public $timestamps = false;
public function players(){
return $this->belongsToMany('Player');
}
}
app/models/User.php
<?php
use Zizaco\Confide\ConfideUser;
class User extends ConfideUser {
protected $table = 'users';
public $timestamps = false;
protected $hidden = array('password');
//Here go original Confide functions
}
app/models/Player.php
<?php
class Player extends User{
public function games(){
return $this->belongsToMany('Game');
}
}
我已经填充了名为 game_player 的数据透视表。当玩家扩展用户时,数据透视表是这样的:
game_player
id
game_id
user_id
但是如果我运行这个超级简单的例子,我会遇到一个错误:
$game = Game::find($gameId);
$player = $game->players(); //Error in this line
错误
Call to undefined method Illuminate\Database\Query\Builder::players()
我很困惑,因为我没有error about pivot table was not found,所以我认为关系创建得很好。
另一方面,如果我 var_dump 我获得的游戏 var:
var_dump($game)
object(Game)[181]
protected 'table' => string 'games' (length=5)
//more var info about DB
protected 'relations' =>
array (size=0)
empty
protected 'hidden' =>
array (size=0)
empty
protected 'visible' =>
array (size=0)
empty
protected 'guarded' =>
如果关系可以很好地创建……关系变量不应该有任何数据吗?
谢谢!
【问题讨论】:
标签: many-to-many laravel pivot-table laravel-4 eloquent