Laravel 通过嵌套的急切加载关系排序

Question

首先，我尝试查看this，但我无法让解决方案发挥作用，因为它涉及数据透视表，而我的却没有。我的大脑无法从那个解决方案中抽象出解决方案。

我有这个问题：

$orderLines = PurchasingOrderLine::where('season_id', '=', $seasonRecID)
        ->with('factory')
        ->with('purchasingFactoryDates.milestone')
        ->with('divergedColors.purchasingColorDates.milestone')
        ->get();

所以关系很大。

我想按milestone 的“数字”属性对purchasingFactoryDates 进行排序。

这是此查询的 JSON 响应示例（示例）..

  {
    id: 1,
    season_id: 258,
    factory_id: 38,
    archived: 0,
    created_at: "2016-10-03 00:00:00",
    updated_at: "2016-10-04 00:00:00",
    factory: {
       ID: 38,
       name: "testfac",
       address: "testadrr",
       postCode: "",
       city: "Foo",
       countryID: 27,
       podID: 2,
       warehouse_id: 3,
       paymentTermID: 11,
       factoryCode: "Bazz",
       active: 1
    },
    purchasing_factory_dates: [
      {
        id: 1,
        purchasing_order_line_id: 1,
        milestone_id: 1,
        milestone_date: "1993-10-22 19:15:51",
        milestone_status_id: 2,
        created_at: "2016-10-04 07:38:30",
        updated_at: "2016-10-18 19:15:51",
        milestone: {
          id: 1,
          name: "test1",
          description: null,
          number: 1,
          created_at: "-0001-11-30 00:00:00",
          updated_at: "-0001-11-30 00:00:00"
        }
      },
    .........

关于如何做到这一点的任何想法？我不希望整个关系按Milestone.number 排序，只按purchasingFactoryDates。

Answer 1

最简单的方法是像这样加入查询：

$orderLines = PurchasingOrderLine::where('season_id', '=', $seasonRecID)
    ->select('purchasing_order_lines.*')
    ->join('purchasing_factory_dates', 'purchasing_factory_dates.purchasing_order_line_id', '=', 'purchasing_order_lines.id')
    ->join('milestone', 'purchasing_factory_dates.milestone_id', '=', 'milestone.id')
    ->with('factory')
    ->with('purchasingFactoryDates.milestone')
    ->with('divergedColors.purchasingColorDates.milestone')
    ->groupBy('purchasing_order_lines.id')
    ->orderBy('milestone.number')
    ->get();

Answer 2

那是Constraining eager loading

$orderLines = PurchasingOrderLine::with('purchasingFactoryDates'=>function($query)
                            {
                              $query->with(['milestone'=>function($query)
                                   {
                                      $query->orderBy('number');
                                    }]);
                            }]);

Answer 3

我认为这可能是您想要的，与您正在查看的其他答案相匹配。

$orderLines = PurchasingOrderLine::where('season_id', '=', $seasonRecID)
    ->with('factory')
    ->with(['purchasingFactoryDates' => function($q) {
        $q->select('purchasingFactoryDates.*')->join('milestone', 'purchasingFactoryDates.milestone_id', '=', 'milestone.id')->orderBy('milestone.number');
    }, 'purchasingFactoryDates.milestone'])
    ->with('divergedColors.purchasingColorDates.milestone')
    ->get();