无法更改 SKView 背景颜色

Question

这是在 iOS 9 中使用的。我无法设置 SKView 的背景颜色，它总是以默认灰色呈现。有没有办法解决这个问题？

let frame = CGRect(x: 0, y: 0, width: 200, height: 100)
let spriteView = SKView(frame: frame)
spriteView.backgroundColor = .blueColor()
self.view.addSubview(spriteView)

运行上述代码时，SKView 是灰色而不是蓝色。我真正想做的是设置allowsTransparency = true，但如果我不能将背景颜色更改为clearColor，我就无法让它工作。

还有其他人遇到这种情况吗？有什么解决方法吗？

更新

即使有@Danilo 的建议，它仍然显示为灰色：

let frame = CGRect(x: 0, y: 0, width: 200, height: 100)
let spriteView = SKView(frame: frame)
spriteView.backgroundColor = .clearColor()
spriteView.allowsTransparency = true
spriteView.opaque = false

更新

显然设置 SKView 的 backgroundColor 没有效果，但如果你将它设置为任何东西，那么 allowsTransparency = true 不起作用。

Answer 1

    let spriteView = SKView(frame: CGRect(x: 0, y: 0, width: 100, height: 100))
    let spriteKitScene = SKScene(size: spriteView.frame.size)
    spriteKitScene.backgroundColor = SKColor.blackColor()
    spriteView.presentScene(spriteKitScene)
    self.view.addSubview(spriteView)

Answer 2

除了添加一个SKView，我们还需要一个SKScene，它由SKView呈现；然后我们调整/更改SKScene 的backgroundColor。反过来，场景将添加一个节点。

例如：

//create a SKView, which takes up the same frame as our view
let spriteView = SKView(frame: self.view.bounds)

//adding spriteView as a child view of our view
self.view.addSubview(spriteView)

//Here, we create a scene, which is the root object of
//the graph
let scene = SKScene(size: spriteView.frame.size)
scene.backgroundColor = .orangeColor()

//As said, we present the scene with our SKView
spriteView.presentScene(scene)

//Here, we create a node, which will be added by our scene
//This node takes up a size that you originally created and has the 
//background color set to blue
let nodeFrame = CGRect(x: 0, y: 0, width: 200, height: 100)
let node = SKSpriteNode(color: .blueColor(), size: nodeFrame.size)

//The following just serves to show how we can adjust the node's   
//position; I will leave that to you
node.position = CGPointMake(scene.frame.size.width - 200, scene.frame.size.height - 100)

//Finally, we add the node to our scene
scene.addChild(node)