【发布时间】:2020-09-16 01:20:45
【问题描述】:
我想用分号分隔符连接我的结果,所以这是我的查询
SELECT
Concat(Year(info.[CreationDate]),'/',Trim('BS-' from info.ProjectN)) As 'AllProjectN'
,part.Designation As 'AllDesignation'
,cust.Name As 'AllCustomer'
,prod.[Quantity] As 'AllQuantity'
,Case when prod.[Quantity] <=3 then prod.[Quantity]
when prod.[Quantity] between 4 and 501 then 3
when prod.[Quantity] between 502 and 1201 then 5
when prod.[Quantity] between 1202 and 1801 then 8
when prod.[Quantity] between 1802 and 3200 then 13
else ' ' end as 'Echantillonnage'
,[GalvaQualityDailyFicheControle].[CreationDate]
FROM [dbo].[GalvaQualityDailyFicheControle]
Inner Join GalvaQualityDailyProduction prod on prod.id= [GalvaQualityDailyFicheControle].FK_idDailyProduction
Inner join GalvaParts part on part.id=prod.[FK_idPart]
Inner join ProjectInfoGalva info on info.id=part.IdProject
inner Join Customer cust on cust.ID=info.FK_Customer
Where Convert(Date,[GalvaQualityDailyFicheControle].[CreationDate]) = '05-27-2020' AND [GalvaQualityDailyFicheControle].FK_idNextProcess=13
Group By
Concat(Year(info.[CreationDate]),'/',Trim('BS-' from info.ProjectN))
,part.Designation
,cust.Name
,prod.[Quantity]
,[GalvaQualityDailyFicheControle].[CreationDate]
我尝试使用 STRING_AGG 得到一行,但数据重复
SELECT
STRING_AGG(Concat(Year(info.[CreationDate]),'/',Trim('BS-' from info.ProjectN)) , ' ;')As 'AllProjectN'
,STRING_AGG(part.Designation , ' ;')As 'AllDesignation'
,STRING_AGG(cust.Name , ' ;')As 'AllCustomer'
,STRING_AGG(prod.[Quantity] , ' ;')As 'AllQuantity'
,STRING_AGG(Case when prod.[Quantity] <=3 then prod.[Quantity]
when prod.[Quantity] between 4 and 501 then 3
when prod.[Quantity] between 502 and 1201 then 5
when prod.[Quantity] between 1202 and 1801 then 8
when prod.[Quantity] between 1802 and 3200 then 13
else ' ' end , ' ;')as 'Echantillonnage'
,[GalvaQualityDailyFicheControle].[CreationDate]
FROM [dbo].[GalvaQualityDailyFicheControle]
Inner Join GalvaQualityDailyProduction prod on prod.id=[GalvaQualityDailyFicheControle].FK_idDailyProduction
Inner join GalvaParts part on part.id=prod.[FK_idPart]
Inner join ProjectInfoGalva info on info.id=part.IdProject
inner Join Customer cust on cust.ID=info.FK_Customer
Where Convert(Date,[GalvaQualityDailyFicheControle].[CreationDate]) = '05-27-2020' AND [GalvaQualityDailyFicheControle].FK_idNextProcess=13
Group By
[GalvaQualityDailyFicheControle].[CreationDate]
如何获取一行而不重复数据?
【问题讨论】:
-
请说明所需的结果。 “一行不重复数据”不清楚。
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这能回答你的问题吗? Produce DISTINCT values in STRING_AGG
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@DavidBrowne-Microsoft 当我运行第一个查询时,我得到两行,当我运行第二个查询时,我应该使用分号作为分隔符从第一行和第二行获取数据,但是当我运行第二个查询时每行重复两次(我应该只得到两个值)
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@MarcGuillot 非常感谢你的帮助,我也从这个帖子stackoverflow.com/a/4473039/9608194得到了很多帮助
标签: sql-server