如何通过laravel中的控制器将数据保存在数据库中

Question

我不知道错误在哪里，数据没有保存到数据库中。任何人都可以帮助我将其全部使用。我被困在这些天了。提前谢谢你。

我的路线

 Route::get('/reject','RejectionReasonsController@index');
 Route::post('/reject','RejectionReasonsController@store');

我的控制器(RejectionReasonsController)

<?php

namespace App\Http\Controllers;

use Illuminate\Http\Request;

class RejectionReasonsController extends Controller
{
    public function index(){

        $record = RejectionReason::all();

        return view('reject');
    }

    public function store(Request $request){


        $record= new RejectionReason();

        $record->reason_title = request('reason_title');

        $record->save();

        return redirect('/routes');

    }
}

我的模型文件（拒绝原因）

<?php

namespace App\Models;

use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;

class RejectionReasons extends Model
{
    protected $fillable = ['reason_title'];
}

我的刀片文件（reject.blade.php）

                <div class="form-check">
                    <form action="/store" class="textbox" method="POST">
                        <h5><b> Select Reasons: </b></h5>
                        <input type="checkbox" id="rejectReason1" name='reason_title[]' value='No responce'> No responce <br>
                        <label for="Rejection">
                            <input type="checkbox" id="rejectReason2" name='reason_title[]' value='Skills mismatch'> Skills mismatch
                        </label>
                        <br />
                        <div id="txtReasonRejected1" style="display: none">
                            <input type="text" id="Reasons1" />
                        </div>
                        <input type="checkbox" id="rejectReason3" name='reason_title[]' value='Culture mismatch'> Culture mismatch <br>
                        <input type="checkbox" id="rejectReason4" name='reason_title[]' value='Salary  expectation mismatch'> Salary  expectation mismatch <br>
                        <label for="Rejection">
                            <input type="checkbox" id="rejectReason5" name='reason_title[]' value='Not enough knowledge/inclination for ColoredCow'> Not enough knowledge/inclination for ColoredCow
                        </label>
                        <br />
                        <div id="txtReasonRejected2" style="display: none">
                            <input type="text" id="Reasons2" />
                        </div>
                        <button type="submit">Reject</button>
                    </form>
                </div>

我不知道错误在哪里，数据没有保存到数据库中。任何人都可以帮助我将其全部使用。我被困在这些天了。提前谢谢你。

Answer 1

如果您绝对确定表单中只有特定数量的“原因”，那么最好在数据库中为每个原​​因创建一列。即

    class RejectionReasons extends Model
    {
     protected $fillable = ['reason_one','reason_two','reason_three' .......];
    }

同样在你的 RejectionController 中，你应该在命名空间之后导入你的模型

   <?php

   namespace App\Http\Controllers;
   
   user RejectionReason;
   use Illuminate\Http\Request;

   class RejectionReasonsController extends Controller
    { ....... }

是的，您的表单也缺少 @csrf 。

Answer 2

首先像这样改变你的路线

Route::post('/reject','RejectionReasonsController@store')->name('reject.post');

然后在你的刀片中

<form action="{{route('reject.post')}}" class="textbox" method="POST">
    @csrf

Answer 3

由于您已将复选框的name 属性的值设置为数组reason_title[]，因此$request->reason_title 的值将是一个字符串数组

如果您希望它位于一条记录中，您可以将其存储为逗号分隔值（使用 implode 辅助函数）

public function store(Request $request){


    $record= new RejectionReason();

    $record->reason_title = implode(",", $request->reason_title);

    $record->save();

    return redirect('/routes');

}

如果您想将每个原因标题存储为新记录，您只需循环它

public function store(Request $request){


    foreach($request->reason_title as $value){
        
        $record= new RejectionReason();

        $record->reason_title = $value;

        $record->save();
    }

    return redirect('/routes');
}

Answer 4

public function store(Request $request){


    $record= new RejectionReason();
    
    $record->reason_title = $request->reason_title;

    $record->save();

    return redirect('/routes');

}

你可以试试

如果你有更多的行，你可以运行一个循环