使用 Jolt 转换转换 JSON答案

【问题标题】：transform JSON with Jolt transform使用 Jolt 转换转换 JSON
【发布时间】：2021-10-05 11:58:06
【问题描述】：

我有一个如下所示的 JSON：

[
  {
    "latency": 9,
    "tx-data-pkts": "14709",
    "rx-data-pkts": "2809",
    "entry-time": 1627585211218,
    "sla-class-index": "0",
    "index": "0"
  },
  {
    "latency": 9,
    "tx-data-pkts": "15418",
    "rx-data-pkts": "3306",
    "entry-time": 1627585211218,
    "sla-class-index": "0",
    "index": "1"
  },
  {
    "latency": 9,
    "tx-data-pkts": "15108",
    "rx-data-pkts": "3485",
    "entry-time": 1627585211218,
    "sla-class-index": "0",
    "index": "0"
  },
  {
    "latency": 9,
    "tx-data-pkts": "15311",
    "rx-data-pkts": "3852",
    "entry-time": 1627585211218,
    "sla-class-index": "0",
    "index": "1"
  }
]

我只需要将数组中的对象带入 index 0 例如

[
  {
    "latency": 9,
    "tx-data-pkts": "14709",
    "rx-data-pkts": "2809",
    "entry-time": 1627585211218,
    "sla-class-index": "0",
    "index": "0"
  },
  {
    "latency": 9,
    "tx-data-pkts": "15108",
    "rx-data-pkts": "3485",
    "entry-time": 1627585211218,
    "sla-class-index": "0",
    "index": "0"
  }
]

请帮帮我

问候

【问题讨论】：

标签： json jolt

【解决方案1】：

您可以使用连续的shift转换；通过在第一个对象中使用"@(0,index)" 值将公共分组对象与键组合，然后从中仅选择零值键，例如

[
  {
    "operation": "shift",
    "spec": {
      "*": "@(0,index)"
    }
  },
  {
    "operation": "shift",
    "spec": {
      "0": {
        "*": "[]"
      }
    }
  }
]

【讨论】：

不客气@JesusBarrios。请您投票。