Javascript获取两个特定工作日之间的工作日答案

【问题标题】：Javascript get weekdays between two specific weekdaysJavascript获取两个特定工作日之间的工作日
【发布时间】：2019-02-24 06:12:16
【问题描述】：

如何获取两个工作日之间的所有工作日名称作为参数？它也应该在超过 7 天后准确返回。

我的星期格式是：

'星期日'，'星期一'，'星期二'，'星期三'，'星期四'，'星期五'， '星期六'

下面的示例和预期输出。谢谢

function day(first, last) {
  var day = new Date();
  var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');

  for (i = 0; i < 14; i++) {
    console.log(week[(day.getDay() + 1 + i) % 7]);
  }

}

day('Tuesday', 'Thursday'); // output should be "Tuesday, Wednesday, Thursday"
day('Friday', 'Tuesday'); // output should be "Friday, Saturday, Sunday, Monday, Tuesday
day('Saturday', 'Monday'); // output should be "Saturday, Sunday, Monday"

【问题讨论】：

所以在您的情况下，您假设该功能仅适用于同年同月（不会发生月份交叉）并且仅以预设方式返回？
@gitguddoge 该函数一周中有两天通过。日期本身并不重要。

标签： javascript date-range dayofweek days

【解决方案1】：

简单，但显而易见且有效：

function day(first, last) {
  var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
  var found = false; 
  for(var i=0; i<week.length; i++) {
    if (!found) {
        if (week[i] == first) found = true;
    }
    if (found) {
        console.log(week[i]);
    }
    if (found && week[i] == last) {
        return;
    }
  }
}

Try it online!

【讨论】：

【解决方案2】：

您可以操作数组以避免使用循环。为清楚起见，对代码进行了注释。

function day(first, last) {
  var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');

  var firstIndex = week.indexOf(first);          //Find first day
  week = week.concat(week.splice(0,firstIndex)); //Shift array so that first day is index 0
  var lastIndex = week.indexOf(last);            //Find last day
  return week.slice(0,lastIndex+1);              //Cut from first day to last day
}

console.log(day('Tuesday', 'Thursday'));
console.log(day('Friday', 'Tuesday'));
console.log(day('Saturday', 'Monday'));

【讨论】：

非常感谢伙计，这看起来干净简单，没有循环和模数。我也喜欢cmets。

【解决方案3】：

我认为你应该为每个工作日设置一个索引。

function day(first, last) {
    var firstIndex;
    var lastIndex;
    var weekDays = [
        { index: 0, name: 'Monday' },
        { index: 1, name: 'Tuesday' },
        { index: 2, name: 'Wednesday' },
        { index: 3, name: 'Thursday' },
        { index: 4, name: 'Friday' },
        { index: 5, name: 'Saturday' },
        { index: 6, name: 'Sunday' }
    ];

    weekDays.forEach(function (item) {
        firstIndex = item.name.toLowerCase() === first.toLowerCase() ? item.index : firstIndex;
        lastIndex = item.name.toLowerCase() === last.toLowerCase() ? item.index : lastIndex;
    });

    if (firstIndex === undefined || lastIndex === undefined) { return; }

    var days = [];
    weekDays.forEach(function (item) {
        if (item.index >= firstIndex && item.index <= lastIndex) {
            days.push(item.name);
        }
    });

    console.log(days.join(', '));
}

【讨论】：

【解决方案4】：

function day(first, last) {
    var day = new Date();
    var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
	var firstIdx = week.indexOf(first), lastIdx = week.indexOf(last);

	var result = [];
	if(lastIdx >= firstIdx) {
		for (var i = firstIdx; i <= lastIdx && i < week.length; i++)
			result.push(week[i]);
	}
	else {
		for (var i = firstIdx; i < week.length; i++)
			result.push(week[i]);
		for (var i = 0; i <= lastIdx && i < week.length; i++)
			result.push(week[i]);
	}
	return result;
}

alert(day('Tuesday', 'Thursday')); // output should be "Tuesday, Wednesday, Thursday"
alert(day('Friday', 'Tuesday')); // output should be "Friday, Saturday, Sunday, Monday, Tuesday
alert(day('Saturday', 'Monday')); // output should be "Saturday, Sunday, Monday"

【讨论】：

【解决方案5】：

试试这个方法

function GetDays(first, last) {
  var day = new Date();
  var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
  var start_index=week.indexOf(first);
  var last_index=week.indexOf(last);
  if(start_index<last_index){
     return week.slice(start_index,last_index+1);
  }
  else{
     return [...week.slice(start_index),...week.slice(0,last_index+1)]
  }
}
console.log(GetDays("Sunday","Tuesday"))
console.log(GetDays("Sunday","Sunday"))

【讨论】：

【解决方案6】：

function day(first, last) {
  var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');

  for (i = 0; i < 7; i++) {
     if(week[i]==first){
        for(j=i ; i< 14 ;j++){ 
            console.log(week[j%7]);
            if(week[j]==end){
               return;
            }
        }

     }
  }

}

day('Tuesday', 'Thursday'); // output should be "Tuesday, Wednesday, Thursday"
day('Friday', 'Tuesday'); // output should be "Friday, Saturday, Sunday, Monday, Tuesday
day('Saturday', 'Monday'); // output should be "Saturday, Sunday, Monday"

【讨论】：

【解决方案7】：

这是你可以做到的一种方法：

function day(first, last) {
  var day = new Date();
  var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
  //Double the array to account for going from end of the week to the beginning
  var weeks = week.concat(week);
  var dayArray = [];
  var activeDay = false;
  //Loop through the large week array. 
  for (var x=0; x<weeks.length; x++) {
     var day = weeks[x];
    //Start adding to the array on the first day
    if (day == first) {
        activeDay = true;
    }
    //Start adding to the array on the first day
    if (activeDay) {
        dayArray.push(day);
      //If the last day then exit
      if (day == last) {
        return dayArray;
      }
    }

  }
    //Return an empty array if no matches
    return [];
}

day('Tuesday', 'Thursday'); // output should be "Tuesday, Wednesday, Thursday"
day('Friday', 'Tuesday'); // output should be "Friday, Saturday, Sunday, Monday, Tuesday
day('Saturday', 'Monday'); // output should be "Saturday, Sunday, Monday"

【讨论】：

【解决方案8】：

我想我只会返回两种不同的情况，具体取决于范围是否超过周末。如果 start 在本周早些时候，这将只返回切片。否则它会分段返回这两个部分：

function day(first, last) {
    var week = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday']
    let start = week.indexOf(first)
    let end = week.indexOf(last)
    return (start > end)
        ? [...week.slice(start), ...week.slice(0, end+1)]
        : week.slice(start, end+1)
  
  }

  console.log(day('Tuesday', 'Thursday'))
  console.log(day('Friday', 'Tuesday'))
  console.log(day('Saturday', 'Monday'))

【讨论】：

【解决方案9】：

类似这样的：

function day(first,last) {
  var week=new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
  var i=week.indexOf(first), result=[];
  do {
    result.push(week[i]);
    i=(i+1) % week.length;
  } while (week[i]!==last);
  result.push(last);
  return result;
}

【讨论】：