WebRequest 等价于 CURL 命令

Question

我正用头撞墙，试图将工作的 curl 命令转换为 c# WebRequest。

我已经阅读了很多帖子，我非常确定我的代码是正确的，但它仍然无法正常工作。

谁能看看我做错了什么？

这是有效的 curl 命令：

curl -k -u x:reallylongstring -H "Content-Type: application/json"  https://api.somewhere.com/desk/external_api/v1/customers.json

这是我用c#写的代码：

WebRequest wrGETURL;
wrGETURL = WebRequest.Create("https://api.somewhere.com/desk/external_api/v1/customers.json");
wrGETURL.Method = "GET";
wrGETURL.ContentType = "application/json"; 
wrGETURL.Credentials = new NetworkCredential("x", "reallylongstring");
Stream objStream = wrGETURL.GetResponse().GetResponseStream();
StreamReader objReader = new StreamReader(objStream);
string responseFromServer = objReader.ReadToEnd();

但是 api 响应：

The remote server returned an error: (406) Not Acceptable.

任何帮助将不胜感激！

谢谢

Answer 1

根据 Nikolaos 的指示，我似乎已使用以下代码解决了这个问题：

public static gta_allCustomersResponse gta_AllCustomers()
    {
        var httpWebRequest = (HttpWebRequest)WebRequest.Create("https://api.somewhere.com/desk/external_api/v1/customers.json");
        httpWebRequest.ContentType = "application/json";
        httpWebRequest.Accept = "*/*";
        httpWebRequest.Method = "GET";
        httpWebRequest.Headers.Add("Authorization", "Basic reallylongstring");

        var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();

        using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
        {
            gta_allCustomersResponse answer =  JsonConvert.DeserializeObject<gta_allCustomersResponse>(streamReader.ReadToEnd());
            return answer;
        }
    }

Answer 2

这是我使用 API 调用或 Web 服务发布 json 数据的解决方案

    public static void PostJsonDataToApi(string jsonData)
    {

        var httpWebRequest = (HttpWebRequest)WebRequest.Create("https://api.somewhere.com/v2/cases");
        httpWebRequest.ReadWriteTimeout = 100000; //this can cause issues which is why we are manually setting this
        httpWebRequest.ContentType = "application/json";
        httpWebRequest.Accept = "*/*";
        httpWebRequest.Method = "POST";
        httpWebRequest.Headers.Add("Authorization", "Basic ThisShouldbeBase64String"); // "Basic 4dfsdfsfs4sf5ssfsdfs=="
        using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
        {
           // we want to remove new line characters otherwise it will return an error
            jsonData= thePostBody.Replace("\n", ""); 
            jsonData= thePostBody.Replace("\r", "");
            streamWriter.Write(jsonData);
            streamWriter.Flush();
            streamWriter.Close();
        }

        try
        {
            HttpWebResponse resp = (HttpWebResponse)httpWebRequest.GetResponse();
            string respStr = new StreamReader(resp.GetResponseStream()).ReadToEnd();
            Console.WriteLine("Response : " + respStr); // if you want see the output
        }
        catch(Exception ex)
        {
         //process exception here   
        }

    }

Answer 3

这是我用来发布 json 数据的 curl 命令：

curl http://IP:PORT/my/path/to/endpoint -H 'Content-type:application/json' -d '[{...json data...}]'

这相当于上面的 C# 中的 curl 命令：

var url = "http://IP:PORT/my/path/to/endpoint";
var jsonData = "[{...json data...}]";

using (var client = new WebClient())
{
    client.Headers.Add("content-type", "application/json");
    var response = client.UploadString(url, jsonData);
}

Answer 4

根据这个关于 406 的问题：What is "406-Not Acceptable Response" in HTTP? 也许您可以尝试在您的请求中添加一个 Accept 标头？也许 curl 会自动添加。

您的 curl 请求中还有一个 -k 告诉它忽略 SSL 验证，我不确定它是否会影响 .NET 代码。换句话说，没有'-k' curl 仍然可以工作吗？然后，不用担心。否则，也许您需要告诉 .NET 也忽略 SSL 验证。