使用 Google 电子表格中的数据预填充 Google 表单

Question

我不是程序员，只是一个试图简化日常任务的 Google 文档用户。我制作了一些非常有用的小脚本，比如一键发送通知电子邮件给其他用户。现在有个棘手的问题不知道怎么解决，找了几天还是没有头绪。

我正在使用Google SpreadSheet。如果我点击“链接”，它应该会打开一个预先设计的 Google 表单，其中包含：WO、Name 和 Engineer 字段，由该行的数据填充。例如：Google 表单的Row 1 应在相应的表单字段中填写4478、AAAAAAAAandDavid`。用户应该能够更改它们。

谢谢大家纠正我的英语不好^^

到目前为止，我可以从调试日志中获取正确的数据。问题是当用户单击“链接”打开 Google 表单时，我不知道如何运行此功能。

    function Finish() {
  var sheetOpen = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Open ticket list");
  var dataOpen = sheetOpen.getDataRange().getValues();
  var cellOpen = sheetOpen.getActiveCell();
  var currentRow = cellOpen.getRow();
  var wo = sheetOpen.getRange(currentRow, 1).getValue();
  var name = sheetOpen.getRange(currentRow, 3).getValue();
  var omEng = sheetOpen.getRange(currentRow, 5).getValue();
  // Browser.msgBox('wo = '+ wo +' and name = '+ name +' and Engineer = '+ omEng);

  var form = FormApp.openById('formid');

  Logger.log('Form Title is '+ form.getTitle()); 

  var allItems = form.getItems();
  Logger.log('Total items in this form '+ allItems.length)

  var woId=0;
  var nameId=0;
  var omEngId=0;

  for (i=0; i < allItems.length ; ++i) {
    var itemTitle = allItems[i].getTitle();
    Logger.log('Item Title '+ itemTitle);

    if (itemTitle == 'wo') {
      woId = allItems[i].getId();
    }
  }

  for (i=0; i < allItems.length ; ++i) {
    var itemTitle = allItems[i].getTitle();
    Logger.log('Item Title '+ itemTitle);

    if (itemTitle == 'name') {
      nameId = allItems[i].getId();
    }
  }

  for (i=0; i < allItems.length ; ++i) {
    var itemTitle = allItems[i].getTitle();
    Logger.log('Item Title '+ itemTitle);

    if (itemTitle == 'Engineer') {
      omEngId = allItems[i].getId();
    }
  }


  var woItem = form.getItemById(woId).asTextItem();
  woItem.createResponse(wo);

  var nameItem = form.getItemById(nameId).asListItem();
  nameItem.createResponse(name);

  var omEngItem = form.getItemById(omEngId).asListItem();  
  omEngItem.createResponse(omEng);


}

Answer 1

主题更改为“Prefill xxx”后，我发现了一个类似的问题，答案很好here。我像这样重新编写代码，效果很好。谢谢大家^__^

function FinishReport() {
  var ss = SpreadsheetApp.getActive();
  var sheet = ss.getSheetByName("Open ticket list");
  var data = ss.getDataRange().getValues();  // Data for pre-fill
  var headers = data[0];  
  var form = FormApp.openByUrl("https://form_url");
  var items = form.getItems();
  var urlCol = headers.indexOf("Finish Report");
  var stopRow = FindStopRowFromOpenTicket();


  // Skip headers, then build URLs for each row in Sheet1.
for (var i = 1; i < stopRow; i++ ) {
    // Create a form response object, and prefill it
    var formResponse = form.createResponse();

    // Prefill WO
    var formItem = items[0].asTextItem();
    var response = formItem.createResponse(data[i][0]);
    formResponse.withItemResponse(response);

    // Prefill Name
    formItem = items[3].asListItem();
    response = formItem.createResponse(data[i][2]);
    formResponse.withItemResponse(response);

    // Prefill Engineer
    formItem = items[4].asListItem();
    response = formItem.createResponse(data[i][4]);
    formResponse.withItemResponse(response);

    // Get prefilled form URL
    var url = formResponse.toPrefilledUrl();
    // Logger.log(url);

    if (urlCol >= 0) {
      var urlRange = sheet.getRange(i+1,urlCol+1).setValue(url);
    }

  }

  // Delete URL of closed ticket
  for (var j = stopRow + 1; j < stopRow + 10; j++) {

    var delUrlRange = sheet.getRange(j, urlCol+1).setValue("");

  } 

};

function FindStopRowFromOpenTicket(){
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Open ticket list");
  var data = sheet.getDataRange().getValues();
  for(var i = data.length-1 ; i >=0 ; i--){
    if (data[i][1] != null && data[i][1] != ''){
      var StopRow = i + 1;
      return StopRow ;
    }
  }
}