您可以使用ServerHttpRequest作为方法参数来获取uri:
@RestController
public class GreetingController {
@GetMapping("/greeting")
public Mono<Greeting> getGreeting(ServerHttpRequest serverHttpRequest) {
return Mono.just(new Greeting("greeting", serverHttpRequest.getURI().toString()));
}
}
如果在负载平衡器后面运行,最好 linkToCurrentResource 应该理解 X-Forwarded-??? 标头。
然后你可以暴露一个ForwardedHeaderTransformer@Bean。
来自其文档:
从“Forwarded”和“X-Forwarded-*”标头中提取值以覆盖请求URI(即HttpRequest.getURI()),使其反映客户端发起的协议和地址。
@Configuration
open class MvcConfig {
@Bean
open fun forwardedHeaderTransformer() = ForwardedHeaderTransformer()
}
这里有一些测试:
@ExtendWith(SpringExtension::class)
@SpringBootTest(webEnvironment = SpringBootTest.WebEnvironment.DEFINED_PORT,
properties = ["server.port=4333"])
class GreetingController2Test {
@Autowired
private lateinit var restTemplate: TestRestTemplate
@Test
fun `should return uri`() {
val responseEntity = restTemplate.getForEntity("/greeting", Greeting::class.java)
val greeting = responseEntity.body!!
assertEquals("http://localhost:4333/greeting", greeting.uri)
}
@Test
fun `should return uri composed from forwarded-??? headers`() {
val headers = HttpHeaders()
headers["X-Forwarded-Host"] = "external-uri.com"
headers["X-Forwarded-Proto"] = "https"
headers["X-Forwarded-Prefix"] = "/prefix"
val httpEntity = HttpEntity(null, headers)
val responseEntity = restTemplate.exchange("/greeting", HttpMethod.GET, httpEntity, Greeting::class.java)
val greeting = responseEntity.body!!
assertEquals("https://external-uri.com/prefix/greeting", greeting.uri)
}
}
还有Greeting.kt:
data class Greeting(
val g: String? = null,
val uri: String? = null
)