【发布时间】:2020-03-26 13:48:03
【问题描述】:
我是新的测试和搜索 3 天以来如何解决我的问题。希望你能帮助我.. 我有一个父组件:
import React from 'react';
import './Subscribe.scss';
import Button from '../../Components/Button/Button';
class Subscribe extends React.Component {
state = {
user: {
firstName: '',
pseudo:'',
email: '',
password:''
}
}
handleChange = (e) => {
this.setState({
user: {...this.state.user, [e.target.name]: e.target.value}
}, () => console.log(this.state))
}
onSubmit = (e) => {
// e.preventDefault()
console.log("you've clicked")
//todo
}
render() {
return(
<form className='subscribe' id='subscriptionForm'>
<label htmlFor='firstName'>Prénom :</label>
<input
data-testid='inputString'
type='text'
name='firstName'
onChange={this.handleChange}
value={this.state.user.firstName}
/>
<label htmlFor='pseudo'>Pseudo :</label>
<input
data-testid='inputString'
type='text'
name='pseudo'
onChange={this.handleChange}
value={this.state.user.pseudo}
/>
<label htmlFor='email'>Email :</label>
<input
data-testid='inputString'
type='email'
name='email'
onChange={this.handleChange}
value={this.state.user.email}
/>
<label htmlFor='password'>
password :
</label>
<Button id='submitSubscription' text='Go go !' onSubmit={this.onSubmit}/>
<Button text='Annuler'/>
</form>
)
}
}
export default Subscribe;
子组件:
import React from "react";
const Button = (props) => {
return (
<button type="button" onClick={props.onClick}>{props.text}</button>
)
}
Button.displayName = 'Button'
export default Button
我想测试它,但没有任何效果......
我的测试:
import React from 'react';
import { shallow, mount } from 'enzyme';
import Subscribe from './Subscribe.js';
import Button from "./../../Components/Button/button.js"
describe('<LogIn />', () => {
it('Should call onSubmit on subscribe component when button component is clicked and allow user to subscribe ', () => {
// Rend le composant et les enfants et renvoie un wrapper Enzyme
const wrapper = mount(<Subscribe />);
// Trouve la première balise bouton
const button = wrapper.find("#submitSubscription");
// Récupère l'instance React du composant
const instance = wrapper.instance();
// Ecoute les appels à la fonction on Submit
jest.spyOn(instance, "onSubmit");
button.simulate('click');
expect(instance.onSubmit).toHaveBeenCalled();
})
评论是我尝试过的。
答案还是Expected number of calls: >= 1 Received number of calls: 0
我也愿意通过反应测试来尝试,我开始了,所以任何帮助都是一种乐趣。
提前致谢!
【问题讨论】:
标签: javascript reactjs jestjs enzyme