如何在发布请求c#中添加正文[重复]

Question

我，尝试将 body 放入请求中，但实际上并没有奏效， 在正文中我想输入 json 格式 {"ClaimNo":"123123"}

我已将其用作代码：

    string ClaimStatus_url  = "https:xyz";
     WebRequest request = WebRequest.Create(ClaimStatus_url);
     request.ContentType = "application/json";
     request.Method = "POST";
     //request.Headers = "";// i used this for puting body in it but did not work
     WebResponse response = request.GetResponse();
     Stream responseStream = response.GetResponseStream();
     StreamReader reader = new StreamReader(responseStream, Encoding.UTF8);
     string result = reader.ReadToEnd();

 
 
 

Answer 1

using System.Text;
using System.Text.Json;

namespace TestPostData;

public class Data
{
    public int ClaimNo { get; set; }
}

public static class Program
{
    public static void Main()
    {
        var postData = new Data
        {
            ClaimNo = 123123,
        };

        var client = new System.Net.Http.HttpClient();

        var content = new StringContent(JsonSerializer.Serialize(postData), Encoding.UTF8, "application/json");

        var response = client.PostAsync("https:xyz", content).Result;
    }
}

这是一个使用 HttpClient 类的示例，现在推荐使用 WebRequest。

Answer 2

试试这个，我希望它会工作。

 var request = (HttpWebRequest)WebRequest.Create("http://www.example.com/recepticle.aspx");

var postData = "thing1=" + Uri.EscapeDataString("hello");
    postData += "&thing2=" + Uri.EscapeDataString("world");
var data = Encoding.ASCII.GetBytes(postData);

request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
request.ContentLength = data.Length;

using (var stream = request.GetRequestStream())
{
    stream.Write(data, 0, data.Length);
}

var response = (HttpWebResponse)request.GetResponse();

var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();

Answer 3

我将从使用 RestSharp 开始。

dotnet add package RestSharp

然后我将创建一个 DTOS 对象，其中包含您要在 json 中发送的内容：

public class DtosObject
{
    public string ClaimNo {get; set;}
}

然后将其作为对象传入（我会将类称为与它包含的数据相关的东西）。如果你只使用 ClaimNo，你也可以像这样使用 KeyValuePair：

var body = new KeyValuePair<string, string>("ClaimNo", "123123");

然后你可以像这样发送请求：

public async Task<IRestResult> PostAsync(string url, object body)
{
    var client = new RestClient(url);
    client.Timeout = -1;

    var request = new RestRequest(Method.Post);
    request.AddJsonBody(body);

    var response = await client.ExecuteAsync(request);
    return response;
}

Answer 4

                  string ClaimStatus_url  = "https://qms.xyz.in/FGClaimWsAPI/api/Common/FetchClaimdetails";

                                        var httpWebRequest = (HttpWebRequest)WebRequest.Create(ClaimStatus_url);
                                        httpWebRequest.ContentType = "application/json";
                                        httpWebRequest.Method = "POST";
                                        using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
                                        {
                                            string json = "{\"ClaimNo\":\""+ userProfile.ClaimNumber +"\"}";
                                            //string json = "{\"ClaimNo\":\"CV010831\"}";
                                            //await turnContext.SendActivityAsync(MessageFactory.Text(json, json), cancellationToken);
                                            streamWriter.Write(json);
                                        }
                                        var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
                                        var result1 = "" ;
                                        using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
                                        {
                                            var result = streamReader.ReadToEnd();
                                            result1 = result.Substring(1, result.Length -2); // to bring response result in proper format
                                                                                             

                                        }

                                        _claimstaus = GenrateJSON_Claim(result1);

上面的代码有效