【发布时间】:2015-08-24 02:31:57
【问题描述】:
我正在尝试编写一个模拟反病毒扫描的代码,它扫描 5 个特定文件,然后创建一个名为 AntiVirusLog.txt 的文件。在此文件中,它会写入结果,例如PSY.avi INFECTED。受感染文件是包含文件youtubesign 中的字符串的文件。
我的问题是,当我尝试将结果打印到文件 AntiVirusLog.txt 时,它不会打印任何内容并将文件留空。
我的代码:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<dirent.h>
#define BUZZ_SIZE 1024
int fast_scan(char *fname, char *str, FILE *fs);
int slow_scan(char *fname, char *str, FILE *fs);
int main(int argc, char *argv[])
{
char name[100];
char choice[5];
char buff[BUZZ_SIZE];
FILE *f7, *f2;
struct dirent *de;
DIR *dr = opendir(argv[1]);
if (dr == NULL) // opendir returns NULL if couldn't open directory
{
printf("Could not open current directory");
return 0;
}
f2 = fopen(argv[2], "rb");
f7 = fopen("AntiVirusLog.txt", "wt");
printf("Welcome to Amnon's Anti-Virus program\n which scan would you like to choose?:\n");
printf("Fast: check only the first and the last 20% of the file\n Slow: Checks the entire file\n");
printf("Enter fast for a fast scan and slow for a slow scan\n");
scanf("%s", choice);
if ((strcmp(choice, "slow"))==0)
{
while ((de = readdir(dr)) != NULL)
{
strcpy(name, argv[1]);
strcat(name, de->d_name);
if((fgets(buff, BUZZ_SIZE, f2)) != NULL)
{
slow_scan(name, buff, f7);
}
}
}
if ((strcmp(choice, "fast")) == 0)
{
while ((de = readdir(dr)) != NULL)
{
strcpy(name, argv[1]);
strcat(name, de->d_name);
if ((fgets(buff, BUZZ_SIZE, f2)) != NULL)
{
fast_scan(name, buff, f7);
}
}
}
printf("The scan was made successfuly, check the file AntiVirusLog.txt to see the results\n");
closedir(dr);
fclose(f2);
fclose(f7);
system("PAUSE");
return (0);
}
int slow_scan(char *fname, char *str, FILE *fs)
{
int findres = 0;
FILE *fp;
char temp[BUZZ_SIZE];
if ((fopen_s(&fp, fname, "rb")) != NULL)
{
return(-1);
}
while ((fgets(temp, BUZZ_SIZE, fp)) != NULL)
{
if ((strstr(temp, str)) != NULL)
{
fprintf(fs, "%s INFECTED\n", fname);
findres++;
}
}
if (findres==0)
{
fprintf(fs, "%s NOT INFECTED\n", fname);
}
fclose(fp);
return(0);
}
int fast_scan(char *fname, char *str, FILE *fs)
{
int findres=0;
int i, j, len, partlen;
FILE *fp;
if ((fopen_s(&fp, fname, "rb")) != NULL)
{
return(-1);
}
fseek(fp, 0, SEEK_END);
len = ftell(fp);
partlen = (len * 20) / 100;
char *temp=malloc(partlen);
while ((fgets(temp, BUZZ_SIZE, fp)) != NULL)
{
for (i = 0; i < partlen; i++)
{
if (temp[i]=str[i])
{
findres++;
}
if (temp[i] != str[i])
{
i = partlen + 1;
}
if (findres == partlen)
{
fprintf(fs, "%s INFECTED\n", fname);
i = partlen + 1;
}
}
for (j = len - partlen; j < len; j++)
{
if (temp[j] = str[j])
{
findres++;
}
if (temp[j] != str[j])
{
j = partlen + 1;
}
if (findres == partlen)
{
fprintf(fs, "%s INFECTED\n", fname);
j = partlen + 1;
}
}
}
if (findres!= partlen)
{
fprintf(fs, "%s NOT INFECTED\n", fname);
}
fclose(fp);
return(0);
}
【问题讨论】:
-
为什么你没有在
main()中检查fopen()? -
wt修饰符对fopen有什么作用?我想我以前没见过…… -
除了其他人说的:打开文件然后关闭它是没有意义的,所以你不需要
f = fopen(argv[1], "rb");和fclose(f);(对于f2,f3,f4, f5, f6 但不是 f7)。此外,您的程序永远不会关闭 f7。 -
@AndreasGrapentin 这是为了指定它是一个文本文件。
-
msdn.microsoft.com/en-us/library/yeby3zcb.aspx 说你是对的。有趣的。这绝对是不标准的。