SQL 查询以获取每年日期范围的最小和最大日期答案

【问题标题】：SQL Query to get min and max date per year date rangesSQL 查询以获取每年日期范围的最小和最大日期
【发布时间】：2015-12-03 20:17:21
【问题描述】：

目前我有一个查询正在加载给定租户的每年销售额。使用下面的代码，我能够产生这个结果（见图片表）

SELECT DATENAME(month,date) [month]
    ,ISNULL(SUM(CASE WHEN YEAR (DATE) = @Year1 THEN gsc END), 0) AS 'Year1'
    ,ISNULL(SUM(CASE WHEN YEAR (DATE) = @Year2 THEN gsc END), 0) AS 'Year2'
    ,ISNULL(SUM(CASE WHEN YEAR (DATE) = @Year3 THEN gsc END), 0) AS 'Year3'
    ,ISNULL(SUM(CASE WHEN YEAR (DATE) = @Year4 THEN gsc END), 0) AS 'Year4'
    ,ISNULL(SUM(CASE WHEN YEAR (DATE) = @Year5 THEN gsc END), 0) AS 'Year5'
INTO #LRSalesAnalysis
FROM dailymod 
WHERE tenantcode = @RP 
GROUP BY DATENAME(month,date)
ORDER BY DATEPART(MM,DATENAME(month,date)+' 01 2011')

部分代码，注意参数@Year1-5 的值类似于 (2011,2012 等)

结果

我现在想要的是获得每年的最短日期和最长日期。结果是这样的

源数据库实际上是每个日期的销售额集合。所以我想获取在给定日期范围（年）中找到的最大和最小日期

任何帮助将不胜感激

【问题讨论】：

标签： sql sql-server sql-server-2008

【解决方案1】：

这是使用您已经使用的相同技术完成的。只有两个查询，一个针对min，一个针对max，您可以将它们与UNION ALL 粘合在一起。

SELECT 
  'Min Date' AS what
  ,MIN(CASE WHEN YEAR(DATE) = @Year1 THEN DATE END) AS 'Year1'
  ,MIN(CASE WHEN YEAR(DATE) = @Year2 THEN DATE END) AS 'Year2'
  ,MIN(CASE WHEN YEAR(DATE) = @Year3 THEN DATE END) AS 'Year3'
  ,MIN(CASE WHEN YEAR(DATE) = @Year4 THEN DATE END) AS 'Year4'
  ,MIN(CASE WHEN YEAR(DATE) = @Year5 THEN DATE END) AS 'Year5'
FROM dailymod 
WHERE tenantcode = @RP 
UNION ALL
SELECT
  'Max Date' AS what
  ,MAX(CASE WHEN YEAR(DATE) = @Year1 THEN DATE END) AS 'Year1'
  ,MAX(CASE WHEN YEAR(DATE) = @Year2 THEN DATE END) AS 'Year2'
  ,MAX(CASE WHEN YEAR(DATE) = @Year3 THEN DATE END) AS 'Year3'
  ,MAX(CASE WHEN YEAR(DATE) = @Year4 THEN DATE END) AS 'Year4'
  ,MAX(CASE WHEN YEAR(DATE) = @Year5 THEN DATE END) AS 'Year5'
FROM dailymod 
WHERE tenantcode = @RP;

【讨论】：