函数不打印 C 文件中的 while 行

Question

我的代码有点问题。我基本上有一个文件，每一行都包含一笔财富。我应该从用户那里得到出生日期，并从那里给出他们的星座和财富。

我有一个包含所有财富的文件。这是我迄今为止的工作：

    //gets position in the array filled with the size of bytes per line
    int ok = 0;
    i = 0;
    j = d.zodiac;

    while(ok == 0 && i < arrSize){
        if(j == zodiacMarker[i]){
            zodiacMarker[i] = -1;
            ok = 1;
        }
        i++;
    }

    locationMark = i - 1;
    printf("\nLocation Mark: %i", locationMark);

    //get the size of the file to get to the specific line in the file
    int finalSize = 0;
    for(int i = 0; i < locationMark; i++){
        finalSize += byteSize[i];
    }

    //goes to the position
    fseek(fp, finalSize+2, SEEK_SET);

    printf("\nFinal Size: %i\n", finalSize);
    printf("Where now: %i\n", ftell(fp));
    printf("Size: %i\n", byteSize[locationMark+1]);
    printf("fgets part : %i\n", byteSize[locationMark]+1);

    char arr[byteSize[locationMark+1]];

    //gets the string in that line
    fgets(arr, byteSize[locationMark]+1, fp);

    printf("%s", arr);

获取每行大小的逻辑的另一件事。我想获取每行的大小并将它们添加到我想要在行中的特定位置。

int charCount( FILE *const fp ){

    char c;
    int count = 0;

    for( ;; ){
        c = fgetc(fp);
        if( c == EOF || c == '\n' )
            break;
        ++count;
    }

    return count;
}

这是我的输出：

Month:4
Day: 8
Aries:
Location Mark: 2
Final Size: 106
Where now: 108
Size: 33
fgets part : 61
Thinking you know something is a sure way to blind yourself.

Month:3
Day: 6
Pisces:
Location Mark: 1
Final Size: 64
Where now: 66
Size: 60
fgets part : 43
ssumption is the mother of all screw-ups.

如您所见，一切都变得很不稳定。我不知道为什么。请发送帮助，如果您对如何解决此问题有更好的建议，请分享。非常感谢！

Answer 1

知道了。我忘了考虑每行的多个\n。所以我去了这个

fseek(fp, finalSize + locationMark, SEEK_SET);