无法删除多边形之间的区域交叉点

Question

我有两个具有不可见和不可移动交叉点的多边形。我试图通过从第一个中删除第二个区域来找到它们之间的区别，然后再次找到交叉点 - 结果交叉点仍然存在并且具有公共区域。为什么会这样？如何去除两个多边形之间的交点并使其边界相接触？

const turf = require("@turf/turf");

const poly1 = [
    [
        [37.367249, 55.615589],
        [37.372462, 55.612478],
        [37.372463, 55.61248],
        [37.453365, 55.564205],
        [37.45336, 55.564206],
        [37.459431, 55.560583],
        [37.558005, 55.682037],
        [37.367249, 55.615589]
    ]
];
const poly2 = [
    [
        [37.336522, 55.603857],
        [37.360725, 55.57621],
        [37.408614, 55.591334],
        [37.371557, 55.613064],
        [37.336522, 55.603857]
    ]
];

const difference = turf.difference(turf.polygon(poly1), turf.polygon(poly2)); // removed poly2 from poly1, difference now is Feature<Polygon>
const intersection = turf.intersect(turf.polygon(difference.geometry.coordinates), turf.polygon(poly2));

if (intersection) { //intersection is geometry collection with polygons
    // why???
}

Answer 1

似乎只是精度问题：如果您检查intersection的区域

if (intersection) {
  console.log(turf.area(intersection));
}

你会看到它是一个 0.28925415367002694 平方米的面积。

如果是可行的解决方案，您可以使用阈值：

const threshold = 1; // configurable 1 square meter

if (intersection && turf.area(intersection) > threshold) {
  console.log("there is intersection");
}

希望这会有所帮助。