如何处理已弃用的函数'unarchiveObject(with:)'？ [关闭]

Question

尝试从这里实现 KeychainWrapper：https://github.com/jrendel/SwiftKeychainWrapper 它运行良好，但在一段代码中我出错了：“'unarchiveObject(with:)' was deprecated in iOS 12.0: Use +unarchivedObjectOfClass:fromData:error: instead”

我尝试关注discussion，看起来很相似，但没有成功。

这段代码在这里：

open func object(forKey key: String, withAccessibility accessibility: KeychainItemAccessibility? = nil) -> NSCoding? {
    guard let keychainData = data(forKey: key, withAccessibility: accessibility) else {
        return nil
    }

    return NSKeyedUnarchiver.unarchiveObject(with: keychainData) as? NSCoding

How to NSKeyedUnarchiver.unarchiveObject

这是更新版本：

open func object(forKey key: String, withAccessibility accessibility: KeychainItemAccessibility? = nil) -> NSCoding? {
guard let keychainData = data(forKey: key, withAccessibility: accessibility) else {
    return nil
}

let result = try! NSKeyedUnarchiver.unarchiveTopLevelObjectWithData(keychainData) as? NSCoding

return result

Answer 1

您可以通过以下方式执行此操作...

let result = jsonDict["result"] as? NSDictionary ?? [:]
let data = try! NSKeyedArchiver.archivedData(withRootObject: result, requiringSecureCoding: false)
UserDefaults.standard.set(data, forKey: "currentUser")

// 从 Userdefault 获取数据

let result = UserDefaults.standard.data(forKey: "currentUser")
    if result != nil{
    let dict = try! NSKeyedUnarchiver.unarchiveTopLevelObjectWithData(result!) as? NSDictionary ?? [:]
    print("Current User Details : - \(dict)")
}

Answer 2

感谢Himanshu Patel 的提示，它对我有用。这是更新的代码：

open func object(forKey key: String, withAccessibility accessibility: KeychainItemAccessibility? = nil) -> NSCoding? {
    guard let keychainData = data(forKey: key, withAccessibility: accessibility) else {
        return nil
    }

    let result = try! NSKeyedUnarchiver.unarchiveTopLevelObjectWithData(keychainData) as? NSCoding

    return result