如何将多维列表中的元素附加到第二个多维列表中

Question

我正在尝试将多维列表中的元素附加到第二个多维列表中。这是我写的代码-

my_list = [[['b', ['a'], 'c'], ['d', ['a', 'b'], 'e']], 
           [['j', ['a', 'f']], ['q', 't']]]
ref_list = [[['q', 'w', 't'], ['y', 'u']], 
            [['s', 'o'], ['p', 'k', 'l']]]

newlist = []
for num, i in enumerate(my_list): 
  small_list = [] 
  for num_1, j in enumerate(i): 
    semilist = []
    for k in j:        
      if isinstance(k, list):      
        onelist = []
        for a in k:
          for ii in ref_list[num][num_1]:
            onelist.append(ii)           
        semilist.append(onelist)
      else:
        semilist.append(k)
    small_list.append(semilist)
  newlist.append(small_list)
      
print(newlist)

我得到的输出是 -

[[['b', ['q', 'w', 't'], 'c'], ['d', ['y', 'u', 'y', 'u'], 'e']], [['j', ['s', 'o', 's', 'o']], ['q', 't']]]

我正在寻找的输出是排序 -

[[['b', ['q', 'w', 't'], 'c'], ['d', ['y', 'u'], 'e']], [['j', ['s', 'o']], ['p', 'k', 'l']]]

我想用“ref_list”的元素替换“my_list”最内层列表的元素。

Answer 1

试试：

my_list = [
    [["b", ["a"], "c"], ["d", ["a", "b"], "e"]],
    [["j", ["a", "f"]], ["q", "t"]],
]

ref_list = [[["q", "w", "t"], ["y", "u"]], [["s", "o"], ["p", "k", "l"]]]


for a, b in zip(my_list, ref_list):
    for i, subl in enumerate(a):
        for ii, v in enumerate(subl):
            if isinstance(v, list):
                subl[ii] = b[i]
                break
        else:
            a[i] = b[i]

print(my_list)

打印：

[
    [["b", ["q", "w", "t"], "c"], ["d", ["y", "u"], "e"]],
    [["j", ["s", "o"]], ["p", "k", "l"]],
]

---

编辑：从第二个列表追加元素而不是替换：

my_list = [
    [["b", ["a"], "c"], ["d", ["a", "b"], "e"]],
    [["j", ["a", "f"]], ["q", "t"]],
]

ref_list = [[["q", "w", "t"], ["y", "u"]], [["s", "o"], ["p", "k", "l"]]]


for a, b in zip(my_list, ref_list):
    for i, subl in enumerate(a):
        for ii, v in enumerate(subl):
            if isinstance(v, list):
                subl[ii].extend(b[i])
                break
        else:
            a[i].extend(b[i])

print(my_list)

打印：

[
    [["b", ["a", "q", "w", "t"], "c"], ["d", ["a", "b", "y", "u"], "e"]],
    [["j", ["a", "f", "s", "o"]], ["q", "t", "p", "k", "l"]],
]

---

EDIT2：在第一个列表的开头添加第二个列表的元素：

my_list = [
    [["b", ["a"], "c"], ["d", ["a", "b"], "e"]],
    [["j", ["a", "f"]], ["q", "t"]],
]

ref_list = [[["q", "w", "t"], ["y", "u"]], [["s", "o"], ["p", "k", "l"]]]


for a, b in zip(my_list, ref_list):
    for i, subl in enumerate(a):
        for ii, v in enumerate(subl):
            if isinstance(v, list):
                subl[ii] = b[i] + subl[ii]
                break
        else:
            a[i] = b[i] + a[i]

print(my_list)

打印：

[
    [["b", ["q", "w", "t", "a"], "c"], ["d", ["y", "u", "a", "b"], "e"]],
    [["j", ["s", "o", "a", "f"]], ["p", "k", "l", "q", "t"]],
]

Answer 2

试试：

ref_list_flat = [l for sublist in ref_list for l in sublist]

for i, l1 in enumerate(my_list):
    for j, l2 in enumerate(l1):
        #check if this is the innermost list
        if not any(isinstance(l3, list) for l3 in l2):
            my_list[i][j] = ref_list_flat.pop(0)
        else:
            for k, l3 in enumerate(l2):
                if isinstance(l3, list):
                    my_list[i][j][k] = ref_list_flat.pop(0)

>>> my_list
[[['b', ['q', 'w', 't'], 'c'], ['d', ['y', 'u'], 'e']],
 [['j', ['s', 'o']], ['p', 'k', 'l']]]