Android 开发：不了解二维数组的每个循环

Question

我在创建一个简单的井字游戏的教程中遇到了这段代码。完整代码可见here

这个 for 循环和 if 有什么作用？当 for 循环循环时，[0],[1],[2] 是否会自增？如果将 2d 数组转换为 1d 数组，它会是什么样子？是否保持相同的位置？

例如

int[][] winningStates = {{0,1,2},{3,4,5},{6,7,8},{0,3,6},{1,4,7},{2,5,8},{0,4,8},{2,4,6}}; 

如果转换成一维数组会是这样吗？：

{0,1,2,3,4,5,6,7,8,0,3,6,1,4,7,2,5,8,0,4,8,2,4,6};

---

int[] gameState = {2,2,2,2,2,2,2,2,2};
int[][] winningStates = {{0,1,2},{3,4,5},{6,7,8},{0,3,6},{1,4,7},{2,5,8},{0,4,8},{2,4,6}};
boolean gameIsActive = true;

for(int[] winningState : winningStates){
            if(gameState[winningState[0]] == gameState[winningState[1]] &&
                    gameState[winningState[1]] == gameState[winningState[2]] &&
                    gameState[winningState[0]] != 2){
                gameIsActive = false;
                String winner = "Black";

                if(gameState[winningState[0]] == 0){
                    winner = "Red";
                }
                //someone has won!
                playAgainMessage again = new playAgainMessage();
                again.playAgainMethod(winner + " has Won !!");
            }

Answer 1

不，for 循环将为winningState 生成以下值（它在数组数组中迭代）：

{0,1,2} -> winningState[0] = 0, winningState[1] = 1, winningState[2] = 2
{3,4,5} -> winningState[0] = 3, winningState[1] = 4, winningState[2] = 5
{6,7,8}
{0,3,6} -> winningState[0] = 0, winningState[1] = 3, winningState[2] = 6
{1,4,7}
{2,5,8}
{0,4,8}
{2,4,6}