如何解析来自这种格式的服务器的 JSON 响应

Question

我有一个来自服务器的 JSON 响应，如下所示：

[
    {
        "user_id": 147,
        "ticket_ref_no": "6ef8b3be-b3b7-4ffb-b8ca-6f114d972553",
        "status": "open",
        "created_at": "2019-08-20 17:08:29",
        "updated_at": "2019-08-20 17:08:29",
        "latestMessage": [
            {
                "message": "Created New Ticket for test",
                "ticket_id": 2,
                "user_id": 147,
                "response_by_user_id": null,
                "created_at": "2019-08-20 17:08:29",
                "updated_at": "2019-08-20 17:08:29"
            }
        ]
    },
    {
        "user_id": 147,
        "ticket_ref_no": "d1c022f2-c12b-45ed-8d74-befc4896c5e2",
        "status": "open",
        "created_at": "2019-08-20 17:22:14",
        "updated_at": "2019-08-20 17:22:14",
        "latestMessage": [
            {
                "message": "Help Test",
                "ticket_id": 3,
                "user_id": 147,
                "response_by_user_id": null,
                "created_at": "2019-08-20 17:22:14",
                "updated_at": "2019-08-20 17:22:14"
            }
        ]
    }
]

我想知道如何解析这些数据，如何将这些数据发送到我的适配器，我尝试过使用：

for (int i = 0; i<data.size(); i++)
   dataMessage = new ArrayList<>(Arrays.asList(data.get(i).getLatestMessage()));

但它只传递最后一条消息，我的意思是 dataMessage 会覆盖最新的消息，但我想要 dataMessage 中的所有消息。 谁能有解决方案？ TIA

Answer 1

但它只传递最后一条消息，我的意思是 dataMessage 会覆盖最新的消息，但我想要 dataMessage 中的所有消息。谁能有解决方案？ TIA

for (int i = 0; i<data.size(); i++)
    dataMessage = new ArrayList<>(Arrays.asList(data.get(i).getLatestMessage()));

问题：

=> 因为您正在迭代循环并将值存储在 dataMessage 变量中，所以显然在循环迭代结束时 dataMessage 将具有最后一个消息值。

解决方案：

无需在循环内初始化 dataMessage，您只需继续添加您在每次迭代中找到的最新消息：

 for (int i = 0; i<data.size(); i++)
        dataMessage.add(data.get(i).getLatestMessage());

Answer 2

只需将= 更改为add 如下：

for (int i = 0; i<data.size(); i++)
        dataMessage.add(Arrays.asList(data.get(i).getLatestMessage());

你也可以使用

Collections.addAll(dataMessage, data.get(i).getLatestMessage());

Answer 3

创建一个模型类，设置从 json 获取的所有值并将该模型类对象添加到 arrarylist 并将该数组列表发送到适配器

Answer 4

创建一个代表您的 Json 结构的 POJO。使用 GSON 等序列化/反序列化库从 json 加载中获取对象。

对于您的回复，类似于此的 POJO 模式会有所帮助。

package com.example;

import java.util.List;
import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;

public class Example {

@SerializedName("user_id")
@Expose
private Integer userId;
@SerializedName("ticket_ref_no")
@Expose
private String ticketRefNo;
@SerializedName("status")
@Expose
private String status;
@SerializedName("created_at")
@Expose
private String createdAt;
@SerializedName("updated_at")
@Expose
private String updatedAt;
@SerializedName("latestMessage")
@Expose
private List<LatestMessage> latestMessage = null;

public Integer getUserId() {
return userId;
}

public void setUserId(Integer userId) {
this.userId = userId;
}

public String getTicketRefNo() {
return ticketRefNo;
}

public void setTicketRefNo(String ticketRefNo) {
this.ticketRefNo = ticketRefNo;
}

public String getStatus() {
return status;
}

public void setStatus(String status) {
this.status = status;
}

public String getCreatedAt() {
return createdAt;
}

public void setCreatedAt(String createdAt) {
this.createdAt = createdAt;
}

public String getUpdatedAt() {
return updatedAt;
}

public void setUpdatedAt(String updatedAt) {
this.updatedAt = updatedAt;
}

public List<LatestMessage> getLatestMessage() {
return latestMessage;
}

public void setLatestMessage(List<LatestMessage> latestMessage) {
this.latestMessage = latestMessage;
}

}
-----------------------------------com.example.LatestMessage.java-----------------------------------

package com.example;

import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;

public class LatestMessage {

@SerializedName("message")
@Expose
private String message;
@SerializedName("ticket_id")
@Expose
private Integer ticketId;
@SerializedName("user_id")
@Expose
private Integer userId;
@SerializedName("response_by_user_id")
@Expose
private Object responseByUserId;
@SerializedName("created_at")
@Expose
private String createdAt;
@SerializedName("updated_at")
@Expose
private String updatedAt;

public String getMessage() {
return message;
}

public void setMessage(String message) {
this.message = message;
}

public Integer getTicketId() {
return ticketId;
}

public void setTicketId(Integer ticketId) {
this.ticketId = ticketId;
}

public Integer getUserId() {
return userId;
}

public void setUserId(Integer userId) {
this.userId = userId;
}

public Object getResponseByUserId() {
return responseByUserId;
}

public void setResponseByUserId(Object responseByUserId) {
this.responseByUserId = responseByUserId;
}

public String getCreatedAt() {
return createdAt;
}

public void setCreatedAt(String createdAt) {
this.createdAt = createdAt;
}

public String getUpdatedAt() {
return updatedAt;
}

public void setUpdatedAt(String updatedAt) {
this.updatedAt = updatedAt;
}

}

使用http://www.jsonschema2pojo.org/转换。