【发布时间】:2019-01-20 15:45:52
【问题描述】:
我做jsonArrayRequest的函数内容是:
JsonArrayRequest jsonArrayRequest = new JsonArrayRequest(Request.Method.POST,
FilesUsed.url_display_thought, null,
new Response.Listener<JSONArray>() {
@Override
public void onResponse(JSONArray response) {
try {
JSONObject jsonObject1 = response.getJSONObject(0);
JSONObject jsonObject2 = response.getJSONObject(1);
if (jsonObject1.getBoolean("error")) {
ArrayList<String> list = new ArrayList<>();
list.add(jsonObject2.getString("message"));
displayThought(list);
} else {
int count = 0;
ArrayList<String> list = new ArrayList<>();
while (count < response.length()) {
try {
JSONObject jsonObject = response.getJSONObject(count);
String thought = jsonObject.getString("post");
list.add(thought);
count++;
} catch (JSONException e) {
e.printStackTrace();
}
}
displayThought(list);
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getApplicationContext(), error.getMessage(), Toast.LENGTH_LONG).show();
error.printStackTrace();
}
}) {
@Override
protected Map<String, String> getParams() throws AuthFailureError {
Map<String, String> params = new HashMap<>();
params.put("email", "sainiakshay04");
return params;
}
};
RequestHandler.getInstance(this).addToRequestQueue(jsonArrayRequest);
它正在使用的 php 的内容是:
require_once '../app/display_personal_account.php';
$response=array();
if(isset($_POST['email'])){
$db = new display_personal_account($_POST['email']);
$res=$db->get_info_added("shared_content");
if($res==1){
$response=$db->display_shared_content();}
else{
$response[]['error']=true;
$response[]['message']="No Content To Display ";}
}
else{
$response[]['error']=true;
$response[]['message']="ERROR: INVALID REQUEST";
}
echo json_encode($response);
?>
但它显示的输出是 ERROR:INVALID REQUEST,虽然我正在使用 getParams 绑定电子邮件,但 php 的 isset 无法正常工作并转到其他部分。 帮助!
【问题讨论】:
标签: android arrays android-volley