用新的自定义序列号替换索引号

Question

我想用一个新的自定义序列号替换当前列表项的索引号

我有一个包含不同变量的列表，它们使用下面的代码进行索引

list_a = ["alpha","beta","romeo","nano","charlie"]

for idx, val in enumerate(list_a, start=1):

print("index number for %s is %d" % (val, idx))

这给了我以下结果。

index number for alpha is 1
index number for beta is 2
index number for romeo is 3
index number for nano is 4
index number for charlie is 5    

现在我想用下面的自定义列表替换上面的索引号从 1 到 5

index number for alpha is 1Red
index number for beta is 2Blue
index number for romeo is 3Purple
index number for nano is 4Red
index number for charlie is 5Blue

在此先感谢您的帮助和非常感谢。

Answer 1

如果我了解您想按特定顺序替换 list_a 的值并且没有逻辑/规则，对吧？

所以你可以用很多方法来做，但如果这样做你会从 list_a 中丢失你的日期，所以我会告诉你另外两种方法来解决这个问题，好吗？！

for的第一种方式：

list_a = ["alpha","beta","romeo","nano","charlie"]
cust_list = ['Red', 'Blue', 'Purple', 'Red', 'Blue'] #create a new list

#Create your logical by for
for id_a, id_b, i in zip(list_a, cust_list, range(5)):
    cust_list[i] = str(i+1)+id_b

#Make some changes in your code and run it
for idx, val in enumerate(list_a, start=1):
    print("index number for %s is %s" % (val, cust_list[idx-1]))

列表理解和for的第二种方式：

list_a = ["alpha","beta","romeo","nano","charlie"]
cust_list = ['Red', 'Blue', 'Purple', 'Red', 'Blue'] #create a new list

#adding new items by list comprehension
[cust_list.insert(i,str(i+1)+cust_list[i]) for i in range(len(list_a))]
#deleting old items
for i in range(5):
    del cust_list[-1]

#Make some changes in your code and run it
for idx, val in enumerate(list_a, start=1):
    print("index number for %s is %s" % (val, cust_list[idx-1]))

您的新数据存储在cust_list，您可以通过print(cust_list)查看。