【发布时间】:2021-12-24 22:11:53
【问题描述】:
我对@987654321@ 和valgrind 有疑问,告诉我Invalid write of size 8。
我已经到了找出错误代码在哪里的地步,但我不知道为什么它是错误的......
我知道还有其他关于此的问题,但它们并没有真正帮助我。
以下是我在一个有点“通用”的堆栈上的方法中最重要部分的摘录,当时我的常规值将是 uintptr_t 类型。
这是我在下面使用的两个定义:
// default stack batch size
#define STACK_BATCH_DEFAULT 8
// size of one value in the stack
#define STACK_SIZEOF_ONE sizeof(uintptr_t)
栈的结构如下:
typedef struct Stack
{
size_t count; // count of values in the stack
size_t size; // size of one value in bytes
size_t alloced; // allocated count
uintptr_t *value; // the values
int batch; // memory gets allocated in those batches
}
Stack;
我有一个堆栈的初始化函数:
bool stack_init(Stack *stack, size_t size, int batch)
{
if(!stack) return false;
stack->batch = batch ? batch : STACK_BATCH_DEFAULT;
stack->size = size;
stack->count = 0;
stack->value = 0;
stack->alloced = 0;
return true;
}
然后是stack_push函数,其中valgrind会抛出错误Invalid write of size 8:
bool stack_push(Stack *stack, uintptr_t *value)
{
if(!stack || !value) return false;
// calculate required amount of elements
size_t required = stack->batch * (stack->count / stack->batch + 1);
// allocate more memory if we need to
if(required > stack->alloced)
{
uintptr_t *tmp = realloc(stack->value, required * stack->size);
if(!tmp) return false;
stack->value = tmp;
stack->alloced = required;
}
// set the value
if(stack->size > STACK_SIZEOF_ONE)
{
memcpy(stack->value + stack->size * stack->count, value, stack->size); // <--- valgrind throws the error here
}
else
{
stack->value[stack->count] = *value;
}
// increment count
stack->count++;
return true;
}
然后在我的程序中调用函数如下:
Stack stack = {0};
stack_init(&stack, sizeof(SomeStruct), 0);
/* ... */
SomeStruct push = { // this is a struct that is larger than STACK_SIZEOF_ONE
.int_a = 0,
.int_b = 0,
.int_c = 0,
.id = 0,
.pt = pointer_to_struct, // it is a pointer to some other struct that was allocated beforehand
};
stack_push(&stack, (uintptr_t *)&push);
对于通用,我的意思是我也可以有一个 常规 堆栈:
Stack stack = {0};
stack_init(&stack, sizeof(uintptr_t), 0);
/* ... */
uintptr_t a = 100;
stack_push(&stack, &a);
另外,如果有任何应该/可以改进的地方,我愿意听取一般提示和建议:)
编辑:下面是一个可运行的代码。
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <stdbool.h>
#include <string.h>
// default stack batch size
#define STACK_BATCH_DEFAULT 8
// size of one value in the stack
#define STACK_SIZEOF_ONE sizeof(uintptr_t)
#define TESTCOUNT 10
#define MAX_BUF 16
typedef struct Stack
{
size_t count; // count of values in the stack
size_t size; // size of one value in bytes
size_t alloced; // allocated count
uintptr_t *value; // the values
int batch; // memory gets allocated in those batches
}
Stack;
typedef struct SomeStruct
{
size_t a;
size_t b;
size_t c;
size_t id;
char *str;
}
SomeStruct;
bool stack_init(Stack *stack, size_t size, int batch)
{
if(!stack) return false;
stack->batch = batch ? batch : STACK_BATCH_DEFAULT;
stack->size = size;
stack->count = 0;
stack->value = 0;
stack->alloced = 0;
return true;
}
bool stack_push(Stack *stack, uintptr_t *value)
{
if(!stack || !value) return false;
// calculate required amount of elements
size_t required = stack->batch * (stack->count / stack->batch + 1);
// allocate more memory if we need to
if(required > stack->alloced)
{
uintptr_t *tmp = realloc(stack->value, required * stack->size);
if(!tmp) return false;
stack->value = tmp;
stack->alloced = required;
}
// set the value
if(stack->size > STACK_SIZEOF_ONE)
{
memcpy(stack->value + stack->size * stack->count, value, stack->size); // <--- valgrind throws the error here
}
else
{
stack->value[stack->count] = *value;
}
// increment count
stack->count++;
return true;
}
bool stack_pop(Stack *stack, uintptr_t *value)
{
if(!stack) return false;
if(!stack->count) return false;
// decrement count of elements
stack->count--;
// return the value if we have an address
if(value)
{
if(stack->size > STACK_SIZEOF_ONE)
{
memcpy(value, stack->value + stack->size * stack->count, stack->size);
}
else
{
*value = stack->value[stack->count];
}
}
int required = stack->batch * (stack->count / stack->batch + 1);
if(required < stack->alloced)
{
uintptr_t *tmp = realloc(stack->value, required * stack->size);
if(!tmp) return false;
stack->value = tmp;
stack->alloced = required;
}
if(!stack->value) return false;
return true;
}
int main(void)
{
// initialize variables
bool valid = false;
Stack default_stack = {0};
Stack some_stack = {0};
// initialize stacks
stack_init(&default_stack, sizeof(uintptr_t), 0);
stack_init(&some_stack, sizeof(SomeStruct), 0);
// test default case - push
printf("Testing the default case, pushing...\n");
for(int i = 0; i < TESTCOUNT; i++)
{
uintptr_t push = i;
valid = stack_push(&default_stack, &push);
if(!valid) return -1;
}
// ...now pop
printf("Testing the default case, popping...\n");
do
{
uintptr_t pop = 0;
valid = stack_pop(&default_stack, &pop);
if(valid) printf("%llu,", pop);
}
while(valid);
printf("\n");
// test some case - push
printf("Testing some case, pushing...\n");
for(int i = 0; i < TESTCOUNT; i++)
{
// generate the push struct
SomeStruct push = {
.a = i * 10,
.b = i * 100,
.c = i * 1000,
.id = i,
.str = 0,
};
// allocate a string
push.str = malloc(MAX_BUF + 1);
snprintf(push.str, MAX_BUF, "%d", i);
// push
valid = stack_push(&some_stack, (uintptr_t *)&push);
if(!valid) return -1;
}
// ...now pop
printf("Testing some case, popping...\n");
do
{
SomeStruct pop = {0};
valid = stack_pop(&some_stack, (uintptr_t *)&pop);
if(valid)
{
printf("a=%d,b=%d,c=%d,id=%d,str=%s\n", pop.a, pop.b, pop.c, pop.id, pop.str);
free(pop.str);
}
}
while(valid);
printf("\n");
/* leave out free functions for this example.... */
return 0;
}
【问题讨论】:
-
对于
push函数来说似乎太复杂了。 -
@EugeneSh。这不是商业代码。这是我的业余时间项目,我是一个喜欢通用事物的人,所以这是我的方法,请检查我的编辑以了解我为什么按照我的方式制作它......不过感谢您的说明!
-
与商业或通用无关。它只是因为它必须做的简单功能而过于复杂。对于您的问题 - 为什么要从指向单个
uintptr_t值的value指针复制整个stack->size? -
目的地地址的计算对我来说也是个谜。
-
@EugeneSh。在你的意思的情况下,我只是分配它......?
memcpy用于当我有一个结构的堆栈,其实际字段我不知道并且大于sizeof(uintptr_t)。在那种情况下,我认为如果我想要一个不知道该结构的实际字段的push函数,我可以/应该复制这些值。
标签: c stack valgrind memcpy memmove