Hangman Part 2 with Arrays Java

Question

现在在课堂上，我们被分配了另一个使用数组的 Hangman 项目，我们必须生成“_”。 当用户输入“wordAnswer”时，我已成功生成所有空格。 我的问题是我不知道如何用空白“_”替换正确的猜测字符。

这是我的整个程序的代码，我知道它并不完整。

import cs1.Keyboard;
public class Game {

    public static void main(String[] args) {
        int correctGuess = 0;
        int wrongGuess = 0;
        int bodyParts = 0;
        char guess;
        boolean foundIt;
        System.out.println("Welcome to Hangman!");
        System.out.println("Please enter a word for the other user to guess!");
        String wordAnswer = Keyboard.readString();
        char[] chars = wordAnswer.toCharArray();
        char[] blanks = new char[wordAnswer.length()];

        System.out.println("You have 6 attempts to guess the word!");
        do {
            for (int i = 0; i < wordAnswer.length(); i++) {
                System.out.print(" _ ");
            }
            System.out.println("Please enter in your guess!");
            guess = Keyboard.readChar();
            for (int i = 0; i < chars.length; i++) {
                if (guess == chars[i]) {
                    blanks[i] = guess;
                    foundIt = true;
                }
            }
        } while (correctGuess < wordAnswer.length() && wrongGuess != 6); {
            System.out.println("Congratulations! You have solved the word!");
        }
    }
}

我知道您必须使用 for 循环才能将空格更改为正确猜测的字母，但是当您运行程序并输入正确的猜测时，空格不会更改为正确的字母。 这是我的输出

 Welcome to Hangman!
Please enter a word for the other user to guess!
program
You have 6 attempts to guess the word!
 _  _  _  _  _  _  _ Please enter in your guess!
p
 _  _  _  _  _  _  _ Please enter in your guess!
r
 _  _  _  _  _  _  _ Please enter in your guess!
o
 _  _  _  _  _  _  _ Please enter in your guess!
g
 _  _  _  _  _  _  _ Please enter in your guess!
r
 _  _  _  _  _  _  _ Please enter in your guess!
a
 _  _  _  _  _  _  _ Please enter in your guess!
m
 _  _  _  _  _  _  _ Please enter in your guess!

我期待的是！！

    Welcome to Hangman!
Please enter a word for the other user to guess!
program
You have 6 attempts to guess the word!
 _  _  _  _  _  _  _ Please enter in your guess!
p
 p  _  _  _  _  _  _ Please enter in your guess!
r
 p  r  _  _  _  _  _ Please enter in your guess!
o
 p  r  o  _  _  _  _ Please enter in your guess!

等等……

这是我所拥有的，但非常感谢提示和帮助！

System.out.println("Please enter in your guess!");
        guess = Keyboard.readChar();
        for (int i = 0; i < chars.length; i++) {
            if (guess == chars[i]) {
                blanks[i] = guess;
                foundIt = true;
            }
        }

Answer 1

行后

char[] blanks = new char[wordAnswer.length()];

添加以下内容：

for(int i = 0; i < wordAnswer.length(); i++) {
    blanks[i] = '_';
}

然后，不要使用System.out.print(" _ ")，而是使用System.out.print(" " + blanks[i] + " ");

您知道，您需要修复do ... while 循环之后的问题。它会错误地告诉这个人他们已经成功地解决了这个词，即使他们没有成功。之后您也不需要{ ... }。此外，你的 foundIt 变量还没有做任何事情，尽管一旦你到达那一点，你将需要它来处理不正确的猜测..

Answer 2

你很亲密。只是一些调整。

紧接着

char[] blanks = new char[wordAnswer.length()];

添加

Arrays.fill(blanks, "_");

或者，如果您不允许使用Arrays 类，则使用旧方法：

for (int i = 0; i < blanks.length; i++) {
   blanks[i] = " _ ";
}

与

代替

for (int i = 0; i < wordAnswer.length(); i++) {
   System.out.print(" _ ");
}

放

for (int i = 0; i < blanks.length; i++) {
      System.out.print(blanks[i]);
}