在python中将多维列表转换为单个字符串

Question

import sys
import math
import numpy as np

alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ "
message = "IFMMPAXPSME"
 
msg = np.array_split(list(message), len(message))
alp = np.array_split(list(alphabet), len(alphabet))
li = []


for i in range(len(msg)):
    for j in range(len(alp)):
        if msg[i] == alp[j]:
            li.append(alp[j-1:j])


print(li)

我得到的结果：

[[array(['H'], dtype='<U1')], [array(['E'], dtype='<U1')], 
[array(['L'], dtype='<U1')], [array(['L'], dtype='<U1')], 
[array(['O'], dtype='<U1')], [], [array(['W'], dtype='<U1')], 
[array(['O'], dtype='<U1')], [array(['R'], dtype='<U1')], 
[array(['L'], dtype='<U1')], [array(['D'], dtype='<U1')]]

谁能帮我解决这个问题？

Answer 1

Nvm，我自己解决了

import numpy as np

alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ "
message = "IFMMPAXPSME"
li = []

def Convert(string):
    list1=[]
    list1[:0]=string
    return list1

def toString(s):
    string = ""
    
    for i in s:
        string += i
        
    return string

msg = Convert(message)
alp = Convert(alphabet)



for i in range(len(msg)):
    for j in range(len(alp)): 
        if msg[i] == alp[j]:  li.append(toString(alp[j-1:j]))


print(''.join(li))