【发布时间】:2012-04-18 10:06:56
【问题描述】:
我正在从 postgres 控制台尝试这个命令:
select sim.id as idsim,
num.id as idnum
from main_sim sim
left join main_number num on (FK_Numbers_id=num.id);
我收到了这样的回复:
错误:列“fk_numbers_id”不存在 LINE 1: ...m from main_sim sim left join main_number num on (FK_Numbers...但如果我只是检查我的表:
dbMobile=# \d main_sim
id | integer | not null default
Iccid | character varying(19) | not null
...
FK_Device_id | integer |
FK_Numbers_id | integer |
Indexes:
"main_sim_pkey" PRIMARY KEY, btree (id)
"main_sim_FK_Numbers_id_key" UNIQUE, btree ("FK_Numbers_id")
"main_sim_Iccid_key" UNIQUE, btree ("Iccid")
"main_sim_FK_Device_id" btree ("FK_Device_id")
Foreign-key constraints:
"FK_Device_id_refs_id_480a73d1" FOREIGN KEY ("FK_Device_id") REFERENCES main_device(id) DEFERRABLE INITIALLY DEFERRED
"FK_Numbers_id_refs_id_380cb036" FOREIGN KEY ("FK_Numbers_id") REFERENCES main_number(id) DEFERRABLE INITIALLY DEFERRED
...我们可以看到该列存在。
可能是语法错误,但我看不到是什么...
任何帮助将不胜感激。 阿莱西奥
【问题讨论】:
-
你试过
sim.FK_Numbers_id而不是FK_Numbers_id吗? -
尝试在引号中输入 FK_Numbers_id,例如“FK_Numbers_id”。作为一个建议:永远不要在 sql 中使用 mized case。
标签: sql postgresql quoted-identifier