如何使用 PHP 更新数组

Question

我有一个使用程序 PHP 编写的应用程序。我创建了一个插入页面，我在其中获取大量地址并将它们作为数组传递并将它们插入数据库中。那里有行的 id，然后是 orderId、地址类型和地址。现在我希望能够更新一个特定的。到目前为止，我已经提出了以下建议：

    // update new supplier order
function updateSupplierOrder($conn, $orderDate, $datePickup, $dateDelivery, $timePickup, $timeDelivery, $car, $carType, $goodsDescription, $paletChange, $paletNo, $supplier, $orderObservation, $paymentDate, $value, $addressPickup, $addressDelivery, $userid, $orderID) {

    $sql1 = "UPDATE suppliersOrders SET supplierId = ?, date = ?, datePickup = ?, timePickup = ?, goodsDescription = ?, dateDelivery = ?, timeDelivery = ?, carType = ?, carNo = ?, paletChange = ?, paletNo = ?, value = ?, invoice = ?, observations = ?, operator = ? WHERE id = ?;";
    $stmt1 = mysqli_stmt_init($conn);
    if (!mysqli_stmt_prepare($stmt1, $sql1)) {
        header ("location: ../suppliersOrders?error=failedupdateorder");
        exit();
    }

    mysqli_stmt_bind_param($stmt1, "isssssssisisssii", $supplier, $orderDate, $datePickup, $timePickup, $goodsDescription, $dateDelivery, $timeDelivery, $carType, $car, $paletChange, $paletNo, $value, $paymentDate, $orderObservation, $userid, $orderID);
    mysqli_stmt_execute($stmt1);
    mysqli_stmt_close($stmt1);

    for ($i=0; $i<count($addressPickup); $i++) {
        
        $address = $addressPickup[$i];
        $type = '1';
    
        $sql2 = "UPDATE suppliersOrdersAddress SET address = ?, operator = ? WHERE orderId = ? AND addressType = ?;";
        $stmt2 = mysqli_stmt_init($conn);   
        if (!mysqli_stmt_prepare($stmt2, $sql2)) {
            header ("location: ../suppliersOrders?error=failedupdateaddress");
            exit();
        }

        mysqli_stmt_bind_param($stmt2, "siii", $address, $userid, $orderID, $type);
        mysqli_stmt_execute($stmt2);
        mysqli_stmt_close($stmt2);

    }

    for ($i=0; $i<count($addressDelivery); $i++) {
        
        $address = $addressDelivery[$i];
        $type = '2';
    
        $sql2 = "UPDATE suppliersOrdersAddress SET address = ?, operator = ? WHERE orderId = ? AND addressType = ?;";
        $stmt2 = mysqli_stmt_init($conn);   
        if (!mysqli_stmt_prepare($stmt2, $sql2)) {
            header ("location: ../suppliersOrders?error=failedupdateaddress");
            exit();
        }

        mysqli_stmt_bind_param($stmt2, "siii", $address, $userid, $orderID, $type);
        mysqli_stmt_execute($stmt2);
        mysqli_stmt_close($stmt2);

    }
        
    header("location: ../suppliersOrders-edit.php?id=$orderID");
}

但这会更新订单和类型的所有地址。如何根据表中的 id 进行更新，这将确保更新正确的地址。

我们将不胜感激。

Answer 1

我找到了问题的解决方案。能够更新我需要的行的最简单方法是从数组中的行中添加 id 值，并根据具有 id 值的 WHERE 子句进行更新。这样我就能够只更新所需的值/行。