按当前日期对数组进行排序

Question

我希望根据当前日期对数组中的值进行排序。

我的价值观：

[{
  date: "12-28",
  id: 1
}, {
  date: "11-30",
  id: 2
}, {
  date: "09-30",
  id: 3
}, {
  date: "05-30",
  id: 4
}]

我试图做这样的事情，但它并没有真正起作用：

var array = [{id: 1, date:'12-28'}, 
{id: 2, date:'11-30'}, 
{id: 3, date:'09-30'}, 
{id: 4, date:'05-30'}];

const now = Date.now();

array.sort(function(a, b) {     
    var c = new Date(a.date);
    var d = new Date(b.date);
    return (now-c)-(now-d);
});

console.log(array);

如果是 11 月 29 日：

[{
  date: "11-30",
  id: 2
}, {
  date: "12-28",
  id: 1
}, {
  date: "05-30",
  id: 4
}, {
  date: "09-30",
  id: 3
}]

Answer 1

将mm-dd转成mmdd再转成数字再使用Math.abs()如下如何？

const arr = [
    {date: "12-28",id: 1}, 
    {date: "11-30",id: 2}, 
    {date: "09-30",id: 3}, 
    {date: "05-30",id: 4}
];

const dt = new Date();
const now = +[dt.getMonth()+1, dt.getDate()].map(v => `0${v}`.slice(-2)).join('');

const ordered = arr.sort((a,b) => Math.abs(+a.date.replace(/[^\d]+/,'') - now) - Math.abs(+b.date.replace(/[^\d]+/,'') - now));

console.log( ordered );

所有日期未来

如果所有日期都被认为是现在或未来，我们可以采用以下概念：

const arr = [
    {date: "12-28",id: 1}, 
    {date: "11-30",id: 2}, 
    {date: "09-30",id: 3}, 
    {date: "05-30",id: 4}
];

//converts m-d to mm-dd
const fmt = md => md.split('-').map(p => `0${p}`.slice(-2)).join('-');
const now = new Date();
const year = new Date().getFullYear();
const nww = fmt(`${now.getMonth()+1}-${now.getDate()}`);
const nw = new Date(`${year}-${nww}`).getTime();

const ordered = arr.map(({
    date: d,
    id
}) => ({
    date: d,
    id,
    d: `${d < nww ? (year + 1) : year}-${d}`
})).map(({
    d,
    ...rest
}) => ({
    ...rest,
    d,
    ...{
        t: new Date(d).getTime()
    }
})).sort((a, b) => (a.t - nw) - (b.t - nw)).map(({
    date,
    id
}) => ({
    date,
    id
}));

console.log( ordered );

Answer 2

您可以使用Array.sort() 为您提供所需的结果，我已将输入数组中的日期移至今年：

let input = [{ date: "2021-12-28", id: 1 }, { date: "2021-11-30", id: 2 }, { date: "2021-09-30", id: 3 }, { date: "2021-05-30", id: 4 }];

function sortByNearest({ date: a}, {date: b}) {
    const now = Date.now();
    return (Math.abs(Date.parse(a) - now)) - (Math.abs(Date.parse(b) - now));
}

console.log(input.sort(sortByNearest))
    

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