合并两个多维数组，同时将它们相交并对值求和答案

【问题标题】：Merging two multidimensional arrays while intersecting them and sum the values合并两个多维数组，同时将它们相交并对值求和
【发布时间】：2018-09-02 09:07:27
【问题描述】：

我有两个多维数组。这些是-

Array
(
    [Fortitude] => Array
        (
            [library_count] => 0
            [crypt_count] => 7
        )

    [Obtenebration] => Array
        (
            [library_count] => 6
            [crypt_count] => 11
        )

    [Dementation] => Array
        (
            [library_count] => 1
            [crypt_count] => 0
        )

    [Obfuscate] => Array
        (
            [library_count] => 0
            [crypt_count] => 2
        )

    [Necromancy] => Array
        (
            [library_count] => 9
            [crypt_count] => 2
        )

    [Celerity] => Array
        (
            [library_count] => 0
            [crypt_count] => 1
        )

    [Redemption] => Array
        (
            [library_count] => 1
            [crypt_count] => 0
        )

    [Dominate] => Array
        (
            [library_count] => 19
            [crypt_count] => 2
        )

    [Auspex] => Array
        (
            [library_count] => 1
            [crypt_count] => 0
        )

    [Potence] => Array
        (
            [library_count] => 1
            [crypt_count] => 2
        )

)

和

Array
(
    [Dominate] => Array
        (
            [library_count] => 19
            [crypt_count] => 7
        )

    [Celerity] => Array
        (
            [library_count] => 0
            [crypt_count] => 6
        )

    [Auspex] => Array
        (
            [library_count] => 1
            [crypt_count] => 2
        )

    [Obtenebration] => Array
        (
            [library_count] => 6
            [crypt_count] => 0
        )

    [Necromancy] => Array
        (
            [library_count] => 9
            [crypt_count] => 1
        )

    [Potence] => Array
        (
            [library_count] => 1
            [crypt_count] => 1
        )

)

.. 这些数组有一些类似的键示例“Celerity”。我想在两个数组中找到公共密钥，并将它们的库和加密计数相加，并将它们变成一个数组。

【问题讨论】：

标签： php arrays sorting multidimensional-array

【解决方案1】：

您可以使用array_intersect() 和array_keys() 来查找在两个数组中都使用的键。然后，遍历键以创建新数组：

$keys1 = array_keys($arr1);
$keys2 = array_keys($arr2);
$common_keys = array_intersect($keys1, $keys2) ;
$diff_keys = array_diff($keys1, $keys2);

$out = [];
foreach ($diff_keys as $diff) {
    if (isset($arr1[$diff])) $out[$diff] = $arr1[$diff];
    else $out[$diff] = $arr2[$diff];
}
foreach ($common_keys as $key) {
    $out[$key] = $arr1[$key] ;
    $out[$key]['library_count'] += $arr2[$key]['library_count'];
    $out[$key]['crypt_count'] += $arr2[$key]['crypt_count'];
}
print_r($out);

输出：

Array
(
    [Fortitude] => Array
        (
            [library_count] => 0
            [crypt_count] => 7
        )

    [Dementation] => Array
        (
            [library_count] => 1
            [crypt_count] => 0
        )

    [Obfuscate] => Array
        (
            [library_count] => 0
            [crypt_count] => 2
        )

    [Redemption] => Array
        (
            [library_count] => 1
            [crypt_count] => 0
        )

    [Obtenebration] => Array
        (
            [library_count] => 12
            [crypt_count] => 11
        )

    [Necromancy] => Array
        (
            [library_count] => 18
            [crypt_count] => 3
        )

    [Celerity] => Array
        (
            [library_count] => 0
            [crypt_count] => 7
        )

    [Dominate] => Array
        (
            [library_count] => 38
            [crypt_count] => 9
        )

    [Auspex] => Array
        (
            [library_count] => 2
            [crypt_count] => 2
        )

    [Potence] => Array
        (
            [library_count] => 2
            [crypt_count] => 3
        )

)

【讨论】：

但它已经从数组中删除了其他键，例如“Fortitude”
我想在一个数组中包含两个数组上的公共键和不常见的键的总和。