合并具有相同键的数组

Question

在一个软件中，我用array_merge函数合并了两个数组。但我需要将相同的数组（当然，使用相同的键）添加到现有数组中。

问题：

 $A = array('a' => 1, 'b' => 2, 'c' => 3);
 $B = array('c' => 4, 'd'=> 5);

 array_merge($A, $B);

 // result
 [a] => 1 [b] => 2 [c] => 4 [d] => 5

如您所见，'c' => 3 丢失了。

那么我怎样才能用相同的键合并所有的？

Answer 1

数组中的两个条目不能共享一个键，您需要更改重复的键

Answer 2

您需要使用array_merge_recursive 而不是array_merge。当然，数组中只能有一个等于'c'的键，但关联的值将是一个同时包含3和4的数组。

Answer 3

试试array_merge_recursive

$A = array('a' => 1, 'b' => 2, 'c' => 3);
$B = array('c' => 4, 'd'=> 5);
$c = array_merge_recursive($A,$B);

echo "<pre>";
print_r($c);
echo "</pre>";

会回来

Array
(
    [a] => 1
    [b] => 2
    [c] => Array
        (
            [0] => 3
            [1] => 4
        )

    [d] => 5
)

Answer 4

 $A = array('a' => 1, 'b' => 2, 'c' => 3);
 $B = array('c' => 4, 'd'=> 5);
 $C = array_merge_recursive($A, $B);
 $aWhere = array();
 foreach ($C as $k=>$v) {

    if (is_array($v)) {
        $aWhere[] = $k . ' in ('.implode(', ',$v).')';
    }
    else {
        $aWhere[] = $k . ' = ' . $v;
    }
 }
 $where = implode(' AND ', $aWhere);
 echo $where;

Answer 5

$arr1 = array(
   "0" => array("fid" => 1, "tid" => 1, "name" => "Melon"),
   "1" => array("fid" => 1, "tid" => 4, "name" => "Tansuozhe"),
   "2" => array("fid" => 1, "tid" => 6, "name" => "Chao"),
   "3" => array("fid" => 1, "tid" => 7, "name" => "Xi"),
   "4" => array("fid" => 2, "tid" => 9, "name" => "Xigua")
);

如果你想把这个数组转换成如下：

$arr2 = array(
   "0" => array(
          "0" => array("fid" => 1, "tid" => 1, "name" => "Melon"),
          "1" => array("fid" => 1, "tid" => 4, "name" => "Tansuozhe"),
          "2" => array("fid" => 1, "tid" => 6, "name" => "Chao"),
          "3" => array("fid" => 1, "tid" => 7, "name" => "Xi")
    ),

    "1" => array(
          "0" =>array("fid" => 2, "tid" => 9, "name" => "Xigua")
     )
);

所以，我的答案是这样的：

$outer_array = array();
$unique_array = array();
foreach($arr1 as $key => $value)
{
    $inner_array = array();

    $fid_value = $value['fid'];
    if(!in_array($value['fid'], $unique_array))
    {
            array_push($unique_array, $fid_value);
            unset($value['fid']);
            array_push($inner_array, $value);
            $outer_array[$fid_value] = $inner_array;


    }else{
            unset($value['fid']);
            array_push($outer_array[$fid_value], $value);

    }
}
var_dump(array_values($outer_array));

希望这个答案会在某个时候对某人有所帮助。

Answer 6

我刚刚写了这个函数，它应该可以为你解决问题，但它确实离开了

public function mergePerKey($array1,$array2)
    {
        $mergedArray = [];

        foreach ($array1 as $key => $value) 
        {
            if(isset($array2[$key]))
             {
               $mergedArray[$value] = null;

               continue;
             }
            $mergedArray[$value] = $array2[$key];
        }

        return $mergedArray;
    }

Answer 7

试试这个：

$array_one = ['ratio_type'];
$array_two = ['ratio_type', 'ratio_type'];
$array_three = ['ratio_type'];
$array_four = ['ratio_type'];
$array_five = ['ratio_type', 'ratio_type', 'ratio_type'];
$array_six = ['ratio_type'];
$array_seven = ['ratio_type'];
$array_eight = ['ratio_type'];

$all_array_elements = array_merge_recursive(
    $array_one,
    $array_two,
    $array_three,
    $array_four,
    $array_five,
    $array_six,
    $array_seven,
    $array_eight
);

foreach ($all_array_elements as $key => $value) {
    echo "[$key]" . ' - ' . $value . PHP_EOL;
}

// OR
var_dump($all_array_elements);