Swift 5 我们如何解析嵌套在字典中的字典，嵌套在另一个字典中？

Question

这是手头的 json。我能够解析除“clientDetails”字典之外的所有数据。这是我的代码。我只是不确定如何映射“clientDetails”字典。我应该采取完全不同的方法吗？还是我在正确的轨道上..

{
  "data": {
    "userID": "124",
    "techID": "1233",
    "clientID": "1",
    "Name": "Haibert",
    "lastName": "Chiem",
    "emailAddress": "haibert@simplygood.com",
    "additionalCompanies": "",
    "clientDetails": {
      "clientID": "1",
      "FirstName": "Sam",
      "LastName": "Ka",
      "email": "rem@simplygood.com",
      "CustomerName": "SimplyRem",
      "BusinessAddress": "9863 N. Glenoaks Blvd, Ste. 207F",
      "BusinessCity": "Burbank",
      "BusinessState": "",
      "BusinessZip": "91502",
      "BusinessCountry": "USA",
      "BusinessPhone": "(818)457-9507",
      "BusinessFax": null,
      "MobilePhone": "818-378-9507",
      "ContactName": "Samuel Kaz",
      "ContactTitle": "Owner",
      "ContactPhone": "818-624-9507",
      "ContactEmail": "sam@simplygood.com",
      "lastUpdated": "2020-10-24 15:09:17"
    }
  }
}

struct UserInformation: Decodable {
    var userID: String = ""
    var clientID: String = ""
    var Name: String = ""
    var lastName: String = ""
    var emailAddress: String = ""
    var techID: String = ""
    var additionalCompanies: String = ""
    
    private enum DataKeys: String, CodingKey {
        case userID = "userID"
        case clientID = "clientID"
        case Name = "Name"
        case lastName = "lastName"
        case emailAddress = "emailAddress"
        case techID = "techID"
        case additionalCompanies = "additionalCompanies"
    }
    
    private enum DataResponseKeys: String, CodingKey {
        case data
    }
    
    init(from decoder: Decoder) throws {
        if let dataResponseContainer = try? decoder.container(keyedBy: DataResponseKeys.self) {
            if let dataContainer = try? dataResponseContainer.nestedContainer(keyedBy: DataKeys.self, forKey: .data) {
                self.userID = try dataContainer.decode(String.self, forKey: .userID)
                self.clientID = try dataContainer.decode(String.self, forKey: .clientID)
                self.Name = try dataContainer.decode(String.self, forKey: .Name)
                self.lastName = try dataContainer.decode(String.self, forKey: .lastName)
                self.emailAddress = try dataContainer.decode(String.self, forKey: .emailAddress)
                self.techID = try dataContainer.decode(String.self, forKey: .techID)
                self.additionalCompanies = try dataContainer.decode(String.self, forKey: .additionalCompanies)
            }
        }
    }
}

Answer 1

试试下面的数据模型

let userInformation = try? JSONDecoder().decode(UserInformation.self, from: jsonData)

import Foundation

// MARK: - UserInformation
struct UserInformation: Codable {
    let data: DataClass
}

// MARK: - DataClass
struct DataClass: Codable {
    let userID, techID, clientID, name: String
    let lastName, emailAddress, additionalCompanies: String
    let clientDetails: ClientDetails

    enum CodingKeys: String, CodingKey {
        case userID, techID, clientID
        case name = "Name"
        case lastName, emailAddress, additionalCompanies, clientDetails
    }
}

// MARK: - ClientDetails
struct ClientDetails: Codable {
    let clientID, firstName, lastName, email: String
    let customerName, businessAddress, businessCity, businessState: String
    let businessZip, businessCountry, businessPhone: String
    let businessFax: String? // null value
    let mobilePhone, contactName, contactTitle, contactPhone: String
    let contactEmail, lastUpdated: String

    enum CodingKeys: String, CodingKey {
        case clientID
        case firstName = "FirstName"
        case lastName = "LastName"
        case email
        case customerName = "CustomerName"
        case businessAddress = "BusinessAddress"
        case businessCity = "BusinessCity"
        case businessState = "BusinessState"
        case businessZip = "BusinessZip"
        case businessCountry = "BusinessCountry"
        case businessPhone = "BusinessPhone"
        case businessFax = "BusinessFax"
        case mobilePhone = "MobilePhone"
        case contactName = "ContactName"
        case contactTitle = "ContactTitle"
        case contactPhone = "ContactPhone"
        case contactEmail = "ContactEmail"
        case lastUpdated
    }
}

如需参考，请遵循
encoding_and_decoding_custom_types Apple documentation

的文档

raywenderlich encoding-and-decoding-in-swift