【发布时间】:2011-04-04 07:16:41
【问题描述】:
我有一个非常简单的问题,关于发送多个查询并将每个结果存储在关联数组中。
基本上,我已将每个查询分配到一个关联数组中。
每个查询的每个结果都进入我的多维数组$el['nameofthequery']['resultsofthequery']
//connection information
$host = "localhost";
$user = "root";
$password = "";
$database = "sghi";
$el = array();
$query = array();
//make connection
$server = mysql_connect($host, $user, $password) or die('Could not connect to mysql server.');
$connection = mysql_select_db($database, $server);
//query the database
$query['mylist1'] = mysql_query("SELECT CompanyName AS label,ContactName AS value FROM suppliers") or die('Could not select database.');
$query['mylist2'] = mysql_query("SELECT ContactTitle AS label,City AS value FROM suppliers") or die('Could not select database.');
//build array of results
// Check if there is any results
if(mysql_num_rows($query['mylist1']) == 0) {
echo "No results found";
exit; // so exit
}
else {
while( $row = mysql_fetch_assoc( $query['mylist1']) ){
$el['mylist1'][] = $row;
}
}
// Check if there is any results
if(mysql_num_rows($query['mylist2']) == 0) {
echo "No results found";
exit; // so exit
}
else {
while( $row = mysql_fetch_assoc( $query['mylist2']) ){
$el['mylist2'][] = $row;
}
}
//echo JSON to page
$response = json_encode($el);
echo $response;
mysql_close($server);
到目前为止一切正常,但是我想知道我是否使用了最好的方法来实现这一点?
这是处理从我上面的代码生成的 json 数据的 jquery 脚本...它在一个表单中填充具有不同值的多个列表:
$.getJSON('test.php', function(result) {
var optionsValues = '';
$.each(result['mylist1'], function(item) {
optionsValues += '<option value="' + this.value + '">' + this.label + '</option>';
});
var options = $('#DestAirportList');
options.append(optionsValues);
var optionsValues = '';
$.each(result['mylist2'], function(item) {
optionsValues += '<option value="' + this.value + '">' + this.label + '</option>';
});
var options = $('#DestAirportRoomList');
options.append(optionsValues);
});
【问题讨论】:
-
请这样格式化您的代码
标签: php mysql multidimensional-array associative-array