同时使用值列表拆分字符串

Question

我有一个字符串和一个列表：

src = 'ways to learn are read and execute.'
temp = ['ways to','are','and']

我想要的是使用列表temp 的值拆分字符串并生成：

['learn','read','execute']

同时。

我试过for循环：

for x in temp:
    src.split(x)

这是它产生的：

['','to learn are read and execute.']
['ways to learn','read and execute.']
['ways to learn are read','execute.']

我想要的是先输出列表中的所有值，然后用它拆分字符串。

有人有解决办法吗？

Answer 1

re.split 是在多个分隔符上拆分的常规解决方案：

import re

src = 'ways to learn are read and execute.'
temp = ['ways to','are','and']

pattern = "|".join(re.escape(item) for item in temp)
result = re.split(pattern, src)
print(result)

结果：

['', ' learn ', ' read ', ' execute.']

您还可以通过简单的列表理解过滤掉空白项并去除空格+标点符号：

result = [item.strip(" .") for item in result if item]
print(result)

结果：

['learn', 'read', 'execute']

Answer 2

这是一种纯粹的pythonic方法，不依赖于正则表达式。它更冗长、更复杂：

result = []
current = 0
for part in temp:
    too_long_result = src.split(part)[1]
    if current + 1 < len(temp): result.append(too_long_result.split(temp[current+1])[0].lstrip().rstrip())
    else: result.append(too_long_result.lstrip().rstrip())
    current += 1
print(result)

如果您不想删除列表条目中的尾随和前导空格，则不能删除 .lstrip().rstrip() 命令。

Answer 3

循环解决方案。您可以根据需要添加条带等条件。

src = 'ways to learn are read and execute.'
temp = ['ways to','are','and']
copy_src = src
result = []
for x in temp:
    left, right = copy_src.split(x)
    if left:
        result.append(left) #or left.strip()
    copy_src = right
result.append(copy_src) #or copy_src.strip()

Answer 4

保持简单

src = 'ways to learn are read and execute.'
temp = ['ways','to','are','and']
res=''
for w1 in src.split():
  if w1 not in temp:
    if w1 not in res.split():
      res=res+w1+" "
 print(res)