C++ 中的 ASCII 艺术答案

【问题标题】：ASCII art in C++C++ 中的 ASCII 艺术
【发布时间】：2016-10-12 11:10:25
【问题描述】：

我正在尝试将ASCII art 放入 C++ 程序中，并通过手动打印每一行来实现，但结果与 ASCII 艺术完全不同。就像：

出现这种情况是因为提示无法识别字符还是我没有正确完成？

这是我正在尝试做的 ASCII 艺术：

_____/\\\\\\\\\________/\\\\\\\\\\\__________/\\\\\\\\\__/\\\\\\\\\\\__/\\\\\\\\\\\_        
 ___/\\\\\\\\\\\\\____/\\\/////////\\\_____/\\\////////__\/////\\\///__\/////\\\///__       
  __/\\\/////////\\\__\//\\\______\///____/\\\/_______________\/\\\_________\/\\\_____      
   _\/\\\_______\/\\\___\////\\\__________/\\\_________________\/\\\_________\/\\\_____     
    _\/\\\\\\\\\\\\\\\______\////\\\______\/\\\_________________\/\\\_________\/\\\_____    
     _\/\\\/////////\\\_________\////\\\___\//\\\________________\/\\\_________\/\\\_____   
      _\/\\\_______\/\\\__/\\\______\//\\\___\///\\\______________\/\\\_________\/\\\_____  
       _\/\\\_______\/\\\_\///\\\\\\\\\\\/______\////\\\\\\\\\__/\\\\\\\\\\\__/\\\\\\\\\\\_ 
        _\///________\///____\///////////___________\/////////__\///////////__\///////////__

代码：

cout << "_____/\\\\\\\\\________/\\\\\\\\\\\__________/\\\\\\\\\__/\\\\\\\\\\\__/\\\\\\\\\\\_        \n";
cout << " ___/\\\\\\\\\\\\\____/\\\/////////\\\_____/\\\////////__\/////\\\///__\/////\\\///__       \n";
cout << "  __/\\\/////////\\\__\//\\\______\///____/\\\/_______________\/\\\_________\/\\\_____      \n";
cout << "  _\/\\\_______\/\\\___\////\\\__________/\\\_________________\/\\\_________\/\\\_____     \n";
cout << "    _\/\\\\\\\\\\\\\\\______\////\\\______\/\\\_________________\/\\\_________\/\\\_____    \n";
cout << "    _\/\\\/////////\\\_________\////\\\___\//\\\________________\/\\\_________\/\\\_____   \n";
cout << "      _\/\\\_______\/\\\__/\\\______\//\\\___\///\\\______________\/\\\_________\/\\\_____  \n";
cout << "       _\///________\///____\///////////___________\/////////__\///////////__\///////////__\n";

【问题讨论】：

显示负责打印的代码
字面意思是 "cout ASCII LINE \n"; 对于所有行
你缺少前导空格并且你的换行符，如果你能真正看到代码，似乎很容易修复
我认为使用 cout << "blablabla" << endl; 而不是 cout << "blablabla\n"; 应该也可以工作......很难说你的 iostream 使用的是什么 endl 类型（我几十年没有使用它）但我敢打赌"\r\n" ...

标签： c++ ascii-art

【解决方案1】：

escape sequences 被解释为单个特殊字符或其他字符，因此输出奇怪。例如"\\" 表示'\'。

您可以使用原始字符串文字：

#include <iostream>

int main()
{
    std::cout << R"(
_____/\\\\\\\\\________/\\\\\\\\\\\__________/\\\\\\\\\__/\\\\\\\\\\\__/\\\\\\\\\\\_        
 ___/\\\\\\\\\\\\\____/\\\/////////\\\_____/\\\////////__\/////\\\///__\/////\\\///__       
  __/\\\/////////\\\__\//\\\______\///____/\\\/_______________\/\\\_________\/\\\_____      
   _\/\\\_______\/\\\___\////\\\__________/\\\_________________\/\\\_________\/\\\_____     
    _\/\\\\\\\\\\\\\\\______\////\\\______\/\\\_________________\/\\\_________\/\\\_____    
     _\/\\\/////////\\\_________\////\\\___\//\\\________________\/\\\_________\/\\\_____   
      _\/\\\_______\/\\\__/\\\______\//\\\___\///\\\______________\/\\\_________\/\\\_____  
       _\/\\\_______\/\\\_\///\\\\\\\\\\\/______\////\\\\\\\\\__/\\\\\\\\\\\__/\\\\\\\\\\\_ 
        _\///________\///____\///////////___________\/////////__\///////////__\///////////__        
)" << '\n';

    return 0;
}

live demo

【讨论】：