PHP如何将数组用于

Question

我有两个这样的数组：

$path = array("Login", "Register");
$list = array("Admin", "Customers", "Guest");

for ($i=0, $i<=count($path), $i++, $k=0; $k<=count($list); $k++) {
    echo "Var " . $path[$i] . " is " . $list[$k] . "\n";
}

输出：

Var Register is Admin
Var Register is Customers
Var Register is Guest
<br />
<b>Notice</b>:  Undefined offset: 3 in <b>[...][...]</b> on line <b>6</b><br />
Var Register is 

我需要输出这个

Var Login is Admin
Var Login is Customers
Var Login is Guest
Var Register is Admin
Var Register is Customers
Var Register is Guest

有解决办法吗？

Answer 1

$path = array("Login", "Register");
$list = array("Admin", "Customers", "Guest");

for ($i=0; $i<count($path); $i++) {
    for($j=0;$j<count($list);$j++){
       echo "Var " . $path[$i] . " is " . $list[$k] . "\n";
    }
}

希望对您有所帮助

Answer 2

如果您只想遍历数组，可以使用foreach 循环：

foreach ($path as $p) {
    $row = 'Var ' . $p . ' is ';
    foreach ($list as $l) {
        echo $row . $l . "\n";
    }
}

第一个循环遍历 var，然后内部循环为每个列表项使用每个 var

Answer 3

<?php
$path = array("Login", "Register");
$list = array("Admin", "Customers", "Guest");

foreach ($path as $row) {
    foreach ($list as $data) {
        echo "Var " . $row . " is " . $data . "\n";
        echo '<br />';
    }
}

你只需要一个双 foreach 循环来解析数组。

输出是：

Var Login is Admin 
Var Login is Customers 
Var Login is Guest 
Var Register is Admin 
Var Register is Customers 
Var Register is Guest 

Answer 4

您需要使用第二个 foreach。

<?php
$path = array("Login", "Register");
$list = array("Admin", "Customers", "Guest");

foreach ($path as $p) {
    foreach ($list as $l) { 
        echo "Var " . $p . " is " . $l . "\n";
    }
}