Typescript：有没有办法获取具有嵌套属性的 Javascript 对象中的所有键？

Question

例如，如果我有

{
   "key1":{
      "key2":[
         {
            "key3":[
               {
                  "key4":{
                     "key5":0
                  }
               },
               {
                  "key6":{
                     "key7":""
                  }
               }
            ]
         },
         {
            "key8":{
               "key9":true
            }
         }
      ]
   }
}

有没有办法像这样得到所有的钥匙？

["key1", "key2", "key3", "key4", "key5", "key6", "key7", "key8", "key9"]

编辑：我在这里尝试了suggestion，但没有成功Typescript: what could be causing this error? "Element implicitly has an 'any' type because type 'Object' has no index signature"

Answer 1

您需要一个递归函数才能进行迭代。

这样试试

var obj = {
  "key1": {
    "key2": [{
      "key3": [{
        "key4": {
          "key5": 0
        }
      }, {
        "key6": {
          "key7": ""
        }
      }]
    }, {
      "key8": {
        "key9": true
      }
    }]
  }
};
var keys = [];

function collectKey(obj) {
  if (obj instanceof Array) {
    //console.log("array");
    for (var i = 0; i < obj.length; i++) {
      collectObj(obj[i]);
    }
  } else if (typeof obj == "object") {
    //console.log("object");
    collectObj(obj)
  } else {
    return;
  }
}

function collectObj(obj) {
  for (var i = 0; i < Object.keys(obj).length; i++) {
    keys.push(Object.keys(obj)[i]);
    collectKey(obj[Object.keys(obj)[i]]);
  }
}
collectKey(obj);
console.log(keys);