正则表达式提取包含三个元音的单词

Question

我正在尝试创建一个函数来从以下字符串中提取具有 3 个连续元音的单词

import re
def three_vowel_words(text):
     pattern =  "[\w]+[aeiou]{3}"
     result = re.findall(pattern, text)
     return result

print(three_vowel_words("Our team was victorious over theirs in the contest."))
#the output should be ["victorious"]

print(three_vowel_words("Obviously, the acquaintance is serious and ambitious.")) 
#the output should be ["Obviously","acquaintance","serious","ambitious"]

但是我得到的输出如下：

["victoriou"]

["Obviou", "acquai", "seriou", "ambitiou"]

谁能帮我纠正我的正则表达式模式，以便提取完整的单词。

谢谢。

Answer 1

将其设为"\w+[aeiou]{3}\w+"，这样单词的其余部分也匹配。使用您当前的解决方案，当找到 3 个连续的元音时匹配停止。

编辑：正如@usr2564301 和@Tomerikoo 所指出的，更通用的方法是"\w*[aeiou]{3}\w*"。这样，以 3 个元音开头或结尾或只有 3 个元音的单词也会被匹配。