【发布时间】:2021-10-19 18:59:15
【问题描述】:
我有一个数据集,我想通过使用 purrr 中的 map() 为每个具有适当标题的变量制作简单的条形图。
我的数据集有 4 个变量,我有一个带有 4 个标题的向量。如何通过这些标题,以便 R 输出一个具有适当标题的图?对于我的最终结果,我想要 4 个地块,每个地块都有适当的标题(而不是 16 个地块,每个地块都是标题和地块的可能排列)。
我试过查看这个answer,但我的标题包含在另一个向量中。这个post 让我尽我所能。
这是我的数据和标题向量:
library(dplyr)
test <- tibble(s1 = c("Agree", "Neutral", "Strongly Disagree"),
s2rl = c("Agree", "Neutral", "Strongly Disagree"),
f1 = c("Strongly Agree", "Disagree", "Strongly Disagree"),
f2rl = c("Strongly Agree", "Disagree", "Strongly Disagree"))
titles <- c("S1 results", "Results for S2RL", "Fiscal Results for F1", "Financial Status of F2RL")
这是我正在构建的自定义函数,它需要 2 个输入、变量和标题(数据集是硬编码的),以及我的地图函数不起作用:
library(purrr)
library(dplyr)
library(ggplot2)
my_plots = function(variable) {
test %>%
count({{variable}}) %>%
mutate(percent = 100*(n / sum(n, na.rm = T))) %>%
ggplot(aes(x = {{variable}}, y = percent, fill = {{variable}})) +
geom_bar(stat = "identity") +
ylab("Percentage") +
ggtitle(paste(title, "N =", n)) +
coord_flip() +
theme_minimal() +
scale_fill_manual(values = c("Strongly disagree" = "#CA001B", "Disagree" = "#1D28B0", "Neutral" = "#D71DA4", "Agree" = "#00A3AD", "Strongly agree" = "#FF8200")) +
scale_x_discrete(labels = c("Strongly disagree" = "Strongly\nDisagree", "Disagree" = "Disagree", "Neutral" = "Neutral", "Agree" = "Agree", "Strongly agree" = "Strongly\nAgree"), drop = FALSE) +
theme(axis.title.y = element_blank(),
axis.text = element_text(size = 9, color = "gray28", face = "bold", hjust = .5),
axis.title.x = element_text(size = 12, color = "gray32", face = "bold"),
legend.position = "none",
text = element_text(family = "Arial"),
plot.title = element_text(size = 14, color = "gray32", face = "bold", hjust = .5)) +
ylim(0, 100)
}
test%>%
map(~my_plots(variable = .x, titles))
【问题讨论】:
标签: r function loops ggplot2 purrr