【发布时间】:2021-10-26 15:29:15
【问题描述】:
我有一个字符向量“A”、“B”、“C”、“D”,并且想循环 n 次以获得所有可能的字符组合 (4^n)。如何编写一个函数来执行这个给定的输入 n?
例如,如果 n=2,我的循环将如下所示:
string <- c('A','B','C','D')
combination = c()
count = 1
for (j in string) {
for (k in string) {
combination[count] <- paste0(j,k)
count = count + 1
}
}
这将产生:
> combination
[1] "AA" "AB" "AC" "AD" "BA" "BB" "BC" "BD" "CA" "CB" "CC" "CD" "DA" "DB" "DC" "DD"
如果n=3,代码如下:
combination = c()
count = 1
for (j in string) {
for (k in string) {
for (l in string) {
combination[count] <- paste0(j,k,l)
count = count + 1
}
}
}
产生
> combination
[1] "AAA" "AAB" "AAC" "AAD" "ABA" "ABB" "ABC" "ABD" "ACA" "ACB" "ACC" "ACD" "ADA" "ADB" "ADC" "ADD" "BAA" "BAB" "BAC"
[20] "BAD" "BBA" "BBB" "BBC" "BBD" "BCA" "BCB" "BCC" "BCD" "BDA" "BDB" "BDC" "BDD" "CAA" "CAB" "CAC" "CAD" "CBA" "CBB"
[39] "CBC" "CBD" "CCA" "CCB" "CCC" "CCD" "CDA" "CDB" "CDC" "CDD" "DAA" "DAB" "DAC" "DAD" "DBA" "DBB" "DBC" "DBD" "DCA"
[58] "DCB" "DCC" "DCD" "DDA" "DDB" "DDC" "DDD"
【问题讨论】:
标签: r loops combinations dna-sequence