【发布时间】:2021-01-23 15:50:20
【问题描述】:
我有一个如下所示的数据框 (df):
> summary(df)
Occurence Group
Min. :0.001 Length:7990
1st Qu.:0.028 Class :character
Median :0.160 Mode :character
Mean :0.195
3rd Qu.:0.307
Max. :0.600
NA's :5473
> unique(df$Group)
[1] "fa20,0" "sa20,0" "fa05,0" "sa10,0" "flatsa,0" "flatfa,0" "fa10,0" "sa05,0" "flatsa,1" "fa10,1" "fa05,1" "sa20,1" "flatfa,1" "fa20,1" "sa10,1" "sa05,1"
我正在尝试使用 density() 函数对每个唯一组的发生率进行核密度估计。我可以一次完成一组:
> flatsa <- density(c(as.numeric(ag04_pattern_long$Occurence[ag04_pattern_long$Group == "flatsa,0"])), na.rm=T)
> flatsa_df2 <- enframe(flatsa$x, value = "X") %>%
+ add_column(Y=flatsa$y) %>%
+ add_column(Group = "flatsa,0") %>%
+ select(-name)
这会为 flatsa_df2 生成此输出:
# A tibble: 512 x 3
X Y Group
<dbl> <dbl> <chr>
1 -0.168 0.00317 flatsa,0
2 -0.166 0.00351 flatsa,0
3 -0.164 0.00387 flatsa,0
4 -0.162 0.00427 flatsa,0
5 -0.161 0.00471 flatsa,0
6 -0.159 0.00519 flatsa,0
7 -0.157 0.00570 flatsa,0
8 -0.155 0.00628 flatsa,0
9 -0.153 0.00689 flatsa,0
10 -0.151 0.00755 flatsa,0
# ... with 502 more rows
如何一次对 df$Group 中的所有 16 个独特元素执行此操作?理想情况下,它们都将进入一个数据框。我试过了:
dens_table <- setDT(ag04_pattern_long)[, .(dens=density(ag04_pattern_long$Occurence, na.rm=T)), by = Group]
for(i in length(unique(ag04_pattern_long$Group))){
dens_table <- density(c(as.numeric(ag04_pattern_long$Occurence[i], na.rm=T)))
}
但是这些都没有产生正确的输出。循环给了我一个错误,说它需要“至少 2 个点来选择带宽”。我认为这表明它没有考虑每个唯一(df$Group)的所有 df$Occurence 值。
救命!
【问题讨论】:
标签: r dataframe for-loop unique kernel-density