如何将此嵌套的对象数组转换为单个对象数组？

Question

我的 api 返回了这个配置文件对象数组：

const profilesData = [
  {
    profile: { id: "26144385", some: "more", other: "misc" },
    photo_details: {
      photos: [{ small: "bar-1", medium: "baz-1" }]
    }
  },
  {
    profile: { id: "26144334", some: "even", other: "some more" },
    photo_details: {
      photos: [
        { small: "bar-2", medium: "baz-2" },
        { small: "fizz-2", medium: "buzz-2" }
      ]
    }
  }
];

我需要对其进行转换，以便得到一个 profileWithPhotos 数组，如下所示：

const profileWithPhotos = [
  {
    id: "26144385",
    some: "more",
    other: "misc",
    photos: [
      {
        small: "bar-1",
        medium: "baz-1"
      }
    ]
  },
  {
    id: "26144334",
    some: "even",
    other: "some more",
    photos: [
      {
        small: "bar-2",
        medium: "baz-2"
      },
      {
        small: "fizz-2",
        medium: "buzz-2"
      }
    ]
  }
];

到目前为止，我已经尝试将解析分解为更小的函数：

const getProfiles = profilesData =>
  profilesData.map(profileData => profileData.profile);

const getSmallAndMediumPic = pic => ({ small: pic.small, medium: pic.medium });

const getPhotos = profilesData =>
  profilesData.map(profileData => profileData.photo_details.photos.map(getSmallAndMediumPic));

const profiles = getProfiles(profilesData);
const photos = getPhotos(profilesData);

const profileWithPhotos = [...profiles, { photos: photos }];

现在我得到了这种对象数组：

​​​​​[ { id: '26144385', some: 'more', other: 'misc' },​​​​​
​​​​​  { id: '26144334', some: 'even', other: 'some more' },​​​​​
​​​​​  { photos: [ [Object], [Object] ] } ]​​​​​

...这不是我想要的。

这是一个working jsbin，上面的代码

我想提取并组合第一个提取的集合与第二个提取的集合。我该怎么做？

Answer 1

您可以使用destructuring assignment 并为数组的每个元素组装一个新对象。

const
    profilesData = [{ profile: { id: "26144385", some: "more", other: "misc" }, photo_details: { photos: [{ small: "bar-1", medium: "baz-1" }] } }, { profile: { id: "26144334", some: "even", other: "some more" }, photo_details: { photos: [{ small: "bar-2", medium: "baz-2" }, { small: "fizz-2", medium: "buzz-2" }] } }],
    result = profilesData.map(
        ({ profile: { id, some, other }, photo_details: { photos } }) =>
        ({ id, some, other, photos })
    );

console.log(result);

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或者spread syntax ... 用于即将发布的 JS 中的对象。这适用于 BABEL。

const
    profilesData = [{ profile: { id: "26144385", some: "more", other: "misc" }, photo_details: { photos: [{ small: "bar-1", medium: "baz-1" }] } }, { profile: { id: "26144334", some: "even", other: "some more" }, photo_details: { photos: [{ small: "bar-2", medium: "baz-2" }, { small: "fizz-2", medium: "buzz-2" }] } }],
    result = profilesData.map(
        ({ profile, photo_details: { photos } }) =>
        ({ ...profile, photos })
    );

console.log(result);

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Answer 2

你可以在对象中使用一些 ES6 参数解构和传播语法来做到这一点。

const profilesData = [{"profile":{"id":"26144385","some":"more","other":"misc"},"photo_details":{"photos":[{"small":"bar-1","medium":"baz-1"}]}},{"profile":{"id":"26144334","some":"even","other":"some more"},"photo_details":{"photos":[{"small":"bar-2","medium":"baz-2"},{"small":"fizz-2","medium":"buzz-2"}]}}]

const result = profilesData.map(({profile, photo_details: {photos}}) => {
  return {...profile, photos}
})

console.log(result)

Answer 3

我觉得一个简单的map 迭代可以满足您的需求。

const result = profilesData.map(data => {
  return {
    id: data.profile.id,
    some: data.profile.some,
    other: data.profile.other,
    photos: data.photo_details.photos
  }
})
console.log(result);

//result
[{
  id: "26144385",
  other: "misc",
  photos: {
     medium: "baz-1",
     small: "bar-1"
  }],
  some: "more"
}, {
  id: "26144334",
  other: "some more",
  photos: {
     medium: "baz-2",
     small: "bar-2"
  }, {
     medium: "buzz-2",
     small: "fizz-2"
  }],
  some: "even"
}]

Answer 4

我将遍历profilesData 数组并创建一个新数组，该数组使用您需要的属性重建对象。有点像..

var data = [];
for(var i=0;i<profilesData.length;i++){
    data[i] = profilesData[i].profile;
    data[i].photos = profilesData[i].photo_details.photos
}
console.log(data);

Answer 5

您可以将array#map 和array#reduce 与Object.assign() 一起使用

const profilesData = [ { profile: { id: "26144385", some: "more", other: "misc" }, photo_details: { photos: [{ small: "bar-1", medium: "baz-1" }] } }, { profile: { id: "26144334", some: "even", other: "some more" }, photo_details: { photos: [ { small:"bar-2", medium: "baz-2" }, { small: "fizz-2", medium: "buzz-2" } ] } } ],
    result = profilesData.map(o => Object.values(o).reduce((r,o) => Object.assign(r, o), {}));
    
console.log(result);

Answer 6

这很简单：

profilesData.map(data => Object.assign({}, data.profile, { photos: data.photo_details.photos }));

或者，如果您只针对最近的环境，或者您正在转译，例如Babel，你可以用parameter destructuring 和object spread 让这个更简洁：

profilesData.map(({profile, photo_details: {photos}}) => ({ ...profile, photos }));

您可以在下面的 sn-p 中看到两者的作用。

const profilesData = [
  {
    profile: { id: "26144385", some: "more", other: "misc" },
    photo_details: {
      photos: [{ small: "bar-1", medium: "baz-1" }]
    }
  },
  {
    profile: { id: "26144334", some: "even", other: "some more" },
    photo_details: {
      photos: [
        { small: "bar-2", medium: "baz-2" },
        { small: "fizz-2", medium: "buzz-2" }
      ]
    }
  }
];

const profilesWithPhotos = profilesData.map(data =>
  Object.assign({}, data.profile, { photos: data.photo_details.photos }));

console.log(profilesWithPhotos);
console.log('-----');

const profilesWithPhotos2 =
  profilesData.map(({profile, photo_details: {photos}}) => ({ ...profile, photos }));

console.log(profilesWithPhotos2);

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Answer 7

好吧，似乎来晚了，但我认为这会奏效 ```

const transformedProfilesData = profilesData.reduce((array, object) => {
  const profile = {...object.profile}
  const photos = object.photo_details.photos.map(photo => photo)
  profile.photos = photos
  array.push(profile)
  return array
}, [])

```