【发布时间】:2019-06-19 09:30:38
【问题描述】:
我正在尝试比较 R 包 ggstatsplot 中给定函数的两个版本的形式。我已经能够在小标题中提取形式,但我似乎无法让这两个表加入。 dplyr::full_join() 会产生一个错误,但并不清楚它的含义。对于如何加入这两个数据框的任何反馈,我们将不胜感激。
# setup
set.seed(123)
library(tidyverse)
library(ggstatsplot)
# formals for the primary version of the function
(df_primary <- tibble::enframe(formals(ggstatsplot::gghistostats)) %>%
dplyr::rename(.data = ., primary = value))
#> # A tibble: 41 x 2
#> name primary
#> <chr> <list>
#> 1 data <NULL>
#> 2 x <missing>
#> 3 binwidth <NULL>
#> 4 bar.measure <chr [1]>
#> 5 xlab <NULL>
#> 6 title <NULL>
#> 7 subtitle <NULL>
#> 8 caption <NULL>
#> 9 type <chr [1]>
#> 10 test.value <dbl [1]>
#> # ... with 31 more rows
# formals for the grouped version of the function
(df_grouped <- tibble::enframe(formals(ggstatsplot::grouped_gghistostats)) %>%
dplyr::rename(.data = ., grouped = value))
#> # A tibble: 43 x 2
#> name grouped
#> <chr> <list>
#> 1 data <missing>
#> 2 x <missing>
#> 3 grouping.var <missing>
#> 4 title.prefix <NULL>
#> 5 binwidth <NULL>
#> 6 bar.measure <chr [1]>
#> 7 xlab <NULL>
#> 8 subtitle <NULL>
#> 9 caption <NULL>
#> 10 type <chr [1]>
#> # ... with 33 more rows
# joining the two dataframes name
dplyr::full_join(
x = df_primary,
y = df_grouped,
by = "name"
)
#> Error: type not supported
traceback()
#> 4: stop(list(message = "type not supported", call = NULL, cppstack = NULL))
#> 3: full_join_impl(x, y, by_x, by_y, aux_x, aux_y, na_matches, environment())
#> 2: full_join.tbl_df(x = tibble::enframe(formals(ggstatsplot::gghistostats)) %>%
#> dplyr::rename(.data = ., primary = value), y = tibble::enframe(formals(ggstatsplot::grouped_gghistostats)) %>%
#> dplyr::rename(.data = ., grouped = value), by = "name")
#> 1: dplyr::full_join(x = tibble::enframe(formals(ggstatsplot::gghistostats)) %>%
#> dplyr::rename(.data = ., primary = value), y = tibble::enframe(formals(ggstatsplot::grouped_gghistostats)) %>%
#> dplyr::rename(.data = ., grouped = value), by = "name")
由reprex package (v0.2.1) 于 2019 年 1 月 25 日创建
【问题讨论】: